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2 years ago

6

the amount of time a certain brand of light bulb lasts is normally distributed with a mean if 1800 hours and a standard deviatio

n of 85 hours. Using the empirical rule, what percentage of light bulbs last between 1630 hours and 1970 hours?

1 answer:

RUDIKE [14]2 years ago

4 0

Answer:

340%

Step-by-step explanation:

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Find the values of x and y that make these triangles congruent by the HL Theorem.

Ymorist [56]

Can you please post a picture of the figure? I don’t see anything

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2 years ago

Describe the transformation from the parent function to the function g(x)=2 times 3^x-4

azamat

Answer:

Step-by-step explanation:

The parent function of g(x) = 2*3^x-4 would be 3^x

The transformation would include: shifting parent function 4 units down (-4) and compressing the function (2)

The movement (shifting) of the graph is caused by the y-intercept. If the y-intercept is positive, the graph moves up and vice versa.

The coefficient which is multiplied determines whether the function is compressed (squeezed) or stretched. If the coefficient is less than 1, then the function is stretched. If the coefficient is greater than 1, then the function is compressed.

6 0

3 years ago

I need help finding 'x'

WITCHER [35]

(8x-10)°+(6x)°+(10x+10)°=360°
8x-10+6x+10x+10=360
8x+6x+10x-10+10=360
24x-10+10=360
24x=360
24x/24=360/24
x=15
Scalene because all three sides are different.

8 0

3 years ago

An example problem in a Statistics textbook asked to find the probability of dying when making a skydiving jump.

MArishka [77]

Answer:

(a) 0.999664

(b) 15052

Step-by-step explanation:

From the given data of recent years, there were about 3,000,000 skydiving jumps and 21 of them resulted in deaths.

So, the probability of death is $\frac{21}{3000000}==0.000007$ .

Assuming, this probability holds true for each skydiving and does not change in the present time.

So, as every skydiving is an independent event having a fixed probability of dying and there are only two possibilities, the diver will either die or survive, so, all skydiving can be regarded as is Bernoulli's trial.

Denoting the probability of dying in a single jump by $q$ .

$q=7\times 10^{-6}=0.000007$ .

So, the probability of survive, $p=1-q$

$\Rightarrow p=1-7\times 10^{-6}=0.999993.$

(a) The total number of jump he made, n=48

Using Bernoulli's equation, the probability of surviving in exactly 48 jumps (r=48) out of 48 jumps (n=48) is

$=\binom(n,r)p^rq^{n-r}$

$=\binom(48,48)(0.999993)^{48}(0.000007)^{48-48}$

$=(0.999993)^{48}=0.999664$ (approx)

So, the probability of survive in 48 skydiving is 0.999664,

(b) The given probability of surviving =90%=0.9

Let, total $n$ skydiving jumps required to meet the surviving probability of 0.9.

So, By using Bernoulli's equation,

$0.9=\binom {n }{r} p^rq^{n-r}$

Here, r=n.

$\Rightarrow 0.9=\binom{n}{n}p^nq^{n-n}$

$\Rightarrow 0.9=p^n$

$\Rightarrow 0.9=(0.999993)^n$

$\Rightarrow \ln(0.9)=n\ln(0.999993)$ [ taking $\log_e$ both sides]

$\Rightarrow n=\frac {\ln(0.9)}{\ln(0.999993)}$

$\Rightarrow n=15051.45$

The number of diving cant be a fractional value, so bound it to the upper integral value.

Hence, the total number of skydiving required to meet the 90% probability of surviving is 15052.

3 0

3 years ago

Both the football and volleyball teams have games today. The football team plays every 7 days. The volleyball team plays every 3

Allisa [31]

They will have games on the same day in 21 days

6 0

3 years ago