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disa [49]
3 years ago
5

Estimate and calculate 16.257 - 9.396

Mathematics
1 answer:
vazorg [7]3 years ago
8 0

Answer:

6.861

Step-by-step explanation:

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PLEASE IF YOU CAN HELP ME!!
gizmo_the_mogwai [7]

Answer: y=-1/4x+3

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Rewrite the expression as a single power with a negative exponent
goblinko [34]

~\hspace{7em}\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} ~\hspace{4.5em} a^n\implies \cfrac{1}{a^{-n}} ~\hspace{4.5em} \cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m} \\\\[-0.35em] ~\dotfill\\\\ \left(\cfrac{1}{3}\cdot \cfrac{1}{3}\cdot \cfrac{1}{3}\cdot \cfrac{1}{3} \right)^2\implies \left[ \left( \cfrac{1}{3} \right)^4 \right]^2\implies \left( \cfrac{1^4}{3^4} \right)^2 \\\\\\ \left( \cfrac{1^{4\cdot 2}}{3^{4\cdot 2}} \right) \implies \cfrac{1}{3^8} \implies 3^{-8}

let's recall that  

\begin{array}{llll} 1^1&=&1\\ 1^{10}&=&1\\ 1^{1,000}&=&1\\ 1^{1,000,000,000}&=&1\\ 1^{1,000,000,000,000}&=&1\\ \end{array}

8 0
2 years ago
Question 1(Multiple Choice Worth 5 points)
Hoochie [10]

Answer:

Q1) D Q2) The final statement Q3) first statement Q4) (0,14) and (10,1)

Step-by-step explanation:

Q1) in this D has the most points therefore highest correlation

Q2) there is no correlation because the points cannot form a linear line

Q3) it does not touch all points but is extreamly close ans is therefore considered a correct linear correlation.

Q4) these points have the closest linear correlation

4 0
2 years ago
Again can you guys help me
Hatshy [7]

Answer:

a

Step-by-step explanation:

slope= rise/run

y-intercept= where the slope intersects with the y-axis

have a great day! :)

5 0
3 years ago
Yochanan walked from home to the bus stop at an average speed of 5 km / h. He immediately got on his school bus and traveled at
kari74 [83]

Answer: 5 km walking and 30 km by bus

Step-by-step explanation:

Yochanan walked from home to the bus stop at an average speed of 5 km / h. He immediately got on his school bus and traveled at an average speed of 60 km / h until he got to school. The total distance from his home to school is 35 km, and the entire trip took 1.5 hours. How many km did Yochanan cover by walking and how many did he cover by travelling on the bus?

walking - 5km/h                                         bus - 60km/h

distance walking - d₁                                 distance bus - d₂

time walking - t₁                                         time bus - t₂

d₁ + d₂ = 35

t₁ + t₂ = 1.5

v = d/t

vwalking = d₁/t₁

5 = d₁/t₁ ⇒ d₁ = 5t₁

vbus = d₂/t₂

60 = d₂/t₂ ⇒ d₂ = 60t₂

d₁ + d₂ = 35 ⇒ 5t₁ + 60t₂ = 35

_________________________

5t₁ + 60t₂ = 35

t₁ + t₂ = 1.5  (*-5)

5t₁ + 60t₂ = 35

-5t₁ -5t₂ = -7.5   (+)

__________________________

55t₂ = 27.5

t₂ = 27.5/55 = 0.5 h

t₁ + t₂ = 1.5 ⇒ t₁ = 1.5 - 0.5 = 1h

d₁ = 5t₁ ⇒ d₁ = 5.1 = 5 km

d₂ = 60t₂ ⇒ d₂ = 30.0.5 = 30 km

6 0
2 years ago
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