Answer:
x = 14
Step-by-step explanation:
5(22-x)=40
5(22-14)=40
5(22)=110 5(-14)=-70
110-70=40
Simple Interest = Principal * Interest Rate * Term
Total Amount = Principal + Simple Interest
<span>
<span>
</span><span><span>
# Principal Interest rate term Interest Total balance
</span><span> 1
<span> 100.00 </span>6% 1
<span> 6.00 </span>
<span> 106.00
</span></span><span> 3
<span> 100.00 </span>6% 2
<span> 12.00 </span>
<span> 112.00
</span></span><span> 5
<span> 100.00 </span>6% 3
<span> 18.00 </span>
<span> 118.00
</span></span><span> 7
<span> 100.00 </span>6% 4
<span> 24.00 </span>
<span> 124.00
</span></span><span> 9
<span> 3,000.00 </span>5% 3
<span> 450.00 </span>
<span> 3,450.00
</span></span><span>10
<span> 4,000.00 </span>6% 3
<span> 720.00 </span>
<span> 4,720.00
</span></span><span>11
<span> 10,000.00 </span>4% 3
<span> 1,200.00 </span>
<span> 11,200.00
</span></span><span>13
<span> 10,000.00 </span>6% 4
<span> 2,400.00 </span>
<span> 12,400.00
</span></span><span>14
<span> 10,000.00 </span>6% 5
<span> 3,000.00 </span>
<span> 13,000.00 </span>
</span></span></span>
The answer will end up being c
Answer:
The relative frequency is found by dividing the class frequencies by the total number of observations
Step-by-step explanation:
Relative frequency measures how often a value appears relative to the sum of the total values.
An example of how relative frequency is calculated
Here are the scores and frequency of students in a maths test
Scores (classes) Frequency Relative frequency
0 - 20 10 10 / 50 = 0.2
21 - 40 15 15 / 50 = 0.3
41 - 60 10 10 / 50 = 0.2
61 - 80 5 5 / 50 = 0.1
81 - 100 <u> 10</u> 10 / 50 = <u>0.2</u>
50 1
From the above example, it can be seen that :
- two or more classes can have the same relative frequency
- The relative frequency is found by dividing the class frequencies by the total number of observations.
- The sum of the relative frequencies must be equal to one
- The sum of the frequencies and not the relative frequencies is equal to the number of observations.