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Nina [5.8K]
3 years ago
8

Which of the folloving statements is the most precise and corred to define perpendicular lines?

Mathematics
1 answer:
svetoff [14.1K]3 years ago
6 0

Answer:C

Step-by-step explanation:

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PLS PLS PLS I NEED HELP FAAAAAAAASSSSST GIVING BRAINLIEST TO QUICKEST CORRECT ​
ElenaW [278]

Answer:

c hope this helps

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
How many terms of the arithmetic sequence {1,22,43,64,85,…} will give a sum of 2332? Show all steps including the formulas used
MA_775_DIABLO [31]

There's a slight problem with your question, but we'll get to that...

Consecutive terms of the sequence are separated by a fixed difference of 21 (22 = 1 + 21, 43 = 22 + 21, 64 = 43 + 21, and so on), so the <em>n</em>-th term of the sequence, <em>a</em> (<em>n</em>), is given recursively by

• <em>a</em> (1) = 1

• <em>a</em> (<em>n</em>) = <em>a</em> (<em>n</em> - 1) + 21 … … … for <em>n</em> > 1

We can find the explicit rule for the sequence by iterative substitution:

<em>a</em> (2) = <em>a</em> (1) + 21

<em>a</em> (3) = <em>a</em> (2) + 21 = (<em>a</em> (1) + 21) + 21 = <em>a</em> (1) + 2×21

<em>a</em> (4) = <em>a</em> (3) + 21 = (<em>a</em> (1) + 2×21) + 21 = <em>a</em> (1) + 3×21

and so on, with the general pattern

<em>a</em> (<em>n</em>) = <em>a</em> (1) + 21 (<em>n</em> - 1) = 21<em>n</em> - 20

Now, we're told that the sum of some number <em>N</em> of terms in this sequence is 2332. In other words, the <em>N</em>-th partial sum of the sequence is

<em>a</em> (1) + <em>a</em> (2) + <em>a</em> (3) + … + <em>a</em> (<em>N</em> - 1) + <em>a</em> (<em>N</em>) = 2332

or more compactly,

\displaystyle\sum_{n=1}^N a(n) = 2332

It's important to note that <em>N</em> must be some positive integer.

Replace <em>a</em> (<em>n</em>) by the explicit rule:

\displaystyle\sum_{n=1}^N (21n-20) = 2332

Expand the sum on the left as

\displaystyle 21 \sum_{n=1}^N n-20\sum_{n=1}^N1 = 2332

and recall the formulas,

\displaystyle\sum_{k=1}^n1=\underbrace{1+1+\cdots+1}_{n\text{ times}}=n

\displaystyle\sum_{k=1}^nk=1+2+3+\cdots+n=\frac{n(n+1)}2

So the sum of the first <em>N</em> terms of <em>a</em> (<em>n</em>) is such that

21 × <em>N</em> (<em>N</em> + 1)/2 - 20<em>N</em> = 2332

Solve for <em>N</em> :

21 (<em>N</em> ² + <em>N</em>) - 40<em>N</em> = 4664

21 <em>N</em> ² - 19 <em>N</em> - 4664 = 0

Now for the problem I mentioned at the start: this polynomial has no rational roots, and instead

<em>N</em> = (19 ± √392,137)/42 ≈ -14.45 or 15.36

so there is no positive integer <em>N</em> for which the first <em>N</em> terms of the sum add up to 2332.

4 0
2 years ago
Solve 5n + 6 = -3n - 10
Verizon [17]

Hi there! :)

Answer:

\huge\boxed{n = -2}

5n + 6 = -3n - 10

Solve for n:

Add 3n to both sides:

5n + 3n + 6 = -3n + 3n - 10

8n + 6 = -10

Subtract 6 from both sides:

8n + 6 - 6 = -10 - 6

8n = -16

Divide both sides by 8:

8n/8 = -16/8

n = -2.

3 0
3 years ago
Read 2 more answers
Which value for the number makes the statement true?
umka21 [38]
A product is the result of multiplication.
A quotient is the result of division.
So you're trying to find the quotient of a number (x) and 5 that equals 8.

Try plugging in the answers. 
  x/5=8

A. x=4
  4/5=8  (Incorrect, 4 divided by 5 is 0.8)

B. x=8
  8/5=8  (Incorrect, 8 divided by 5 is 1.6)

C. x=40
  40/5=8  (Correct, 40 divided by 5 is 8)

D. x=80
  80/5=8  (Incorrect, 80 divided by 5 is 16)

So your answer is C. 40
The quotient of 40 and 5 is 8.
3 0
3 years ago
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S_A_V [24]
#6 is 1.5 hours (Maria)
4 0
3 years ago
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