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3 years ago

9

Solve the system of equations 3y + 2z = 12 and y – z= 9.

1 answer:

dangina [55]3 years ago

3 0

$\left\{\begin{array}{ccc}3y+2z=12\\y-z=9&|multiply\ both\ sides\ by\ 2\end{array}\right\\\underline{+\left\{\begin{array}{ccc}3y+2z=12\\2y-2z=18\end{array}\right}\\.\ \ \ \ 5y=30\ \ \ |divide\ both\ sides\ by\ 5\\.\ \ \ \ y=6\\\\subtitute\ the\ value\ of\ y\ to\ the\ equation\ y-z=9\\\\6-z=9\ \ \ |subtract\ 6\ from\ both\ sides\\-z=3\ \ \ |change\ signs\\z=-3\\\\Answer:\left\{\begin{array}{ccc}y=6\\z=-3\end{array}\right$

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The answer is 10.5 pounds. No there is no other solutions.

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3 years ago

Three cards are drawn at random from a standard deck of cards, without replacement. Find the probability that the suits of the c

Evgesh-ka [11]

The probability that suits of cards are spades, hearts, and spades is 39/850 or 0.046.

According to the give question.

Three cards are drawn from a standard deck of cards without replacement.

Since,

The total number of cards in a standard deck = 52

Total number of spade cards = 13

Total number of heart cards = 13

Now,

The probabbility of getting first card as a spade card = 13/52 = 1/4

The probability of getting second card as heart card

= 13/(52 -1) (cards are drawn without replacement)

= 13/51

The probability of getting third card as a spade card

= (13 - 1)/52 -2

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Therefore, the probability that suits of the cards are spades, hearts, spades

= 1/4 × 13/51 × 6/25

= 39/850

= 0.046

Hence, the probability that suits of cards are spades, hearts, and spades is 39/850 or 0.046.

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1 year ago

An engineer is designing a storage compartment in a spacecraft .The compartment must be 2 meters longer than it is wide, and its

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Answer:

Let x be the width of the compartment,

Then according to the question,

The length of the compartment = x + 2

And the depth of the compartment = x -1

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If $x-2=0\implies x = 2$ and if $x^2+3x+4=0\implies x = \text{complex number}$

But, width can not be the complex number.

Therefore, width of the compartment = 2 meter.

Length of the compartment = 2 + 2 = 4 meter.

And, Depth of the compartment = 2 - 1 = 1 meter.

Since, the function that shows the volume of the compartment is,

$V(x) = x^3 + x^2 - 2x$

When we lot the graph of that function we found,

V(x) is maximum for infinite.

But width can not infinite,

Therefore, the maximum value of V(x) will be 8.

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Answer:

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