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2 years ago

4m^2 + 4m + 1 = 0 quadratic formula

Mathematics

1 answer:

Alex73 [517]2 years ago

4 0

X= -0.5. Get Desmos, it's really helpful for this sort of thing.

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It is called a heptahedron

Step-by-step explanation:

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2 years ago

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1 year ago

GCSE 995381

nikdorinn [45]

Answer:

$2.9 cm^2$

Step-by-step explanation:

Given,

Angle of sector = 30°

Radius of circle, r = 8 cm

Area of the shaded region, A =?

The diagram is attached below.

Now,

Area of shaded region = Area of sector - Area of triangle

Area of triangle = $\frac{1}{2}\times base \times height$

We know that,

$\sin \theta = \dfrac{P}{H}$

$\sin 30^\circ= \dfrac{P}{8}$

$P = \dfrac{8}{2}$

$P = 4\ cm$

And

$\cos \theta =\dfrac{B}{H}$

$\cos 30^\circ = \dfrac{B}{8}$

$B = \dfrac{8\times \sqrt{3}}{2}$

$B = 4\sqrt 3$

Area of sector = $\dfrac{\theta}{360^\circ}\times \pi r^2$

Area of sector = $\dfrac{30^\circ}{360^\circ}\times \pi \times 8^2$

= 16.75 cm^2

Area of triangle = $\dfrac{1}{2} \times 4\sqrt 3 \times 4$

= 13.85 cm^2

Area of shaded region = 16.75 - 13.85

= $2.9 cm^2$

7 0

2 years ago