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tester [92]
2 years ago
11

Need help with systems of equations

Mathematics
1 answer:
OLEGan [10]2 years ago
8 0

Step-by-step explanation:

x + y = 14

this gives us

y = 14 - x

2x = y - 5

we use the first equation in the second

2x = 14 - x - 5 = 9 - x

3x = 9

x = 3

y = 14 - x = 14 - 3 = 11

the smallest number is 3 or 03.

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Answer:

shes less likely to pick blue from the second bag

Step-by-step explanation:

first you divide 10 by 25 which will give you 40 percent

then

you divide 75 by 250 which will give you 30 percent

which makes it less likely for Greg to pick blue from the second bag

8 0
3 years ago
Fine the distance between the points A(2,-1) & B(-4,2)
nalin [4]
Answer is below........

8 0
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Adrian is putting streamers across the ceiling of his dining room to decorate for his nephew’s birthday party. The ceiling is re
ale4655 [162]

Answer: hello there here is your answer:

17.5 feet

Step-by-step explanation:

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7 0
3 years ago
Read 2 more answers
Evaluate 4 + (-2)= PLEASE HELP IF YOU KNOW THE ANSWER PLEASE SHOW WORK!? THANK YOU!
Phoenix [80]

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8 0
4 years ago
Suppose that a box contains one fair coin (Heads and Tails are equally likely) and one coin with Heads on each side. Suppose fur
stealth61 [152]

Using conditional probability, it is found that there is a 0.1 = 10% probability that the chosen coin was the fair coin.

Conditional Probability

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

  • P(B|A) is the probability of event B happening, given that A happened.
  • P(A \cap B) is the probability of both A and B happening.
  • P(A) is the probability of A happening.

In this problem:

  • Event A: Three heads.
  • Event B: Fair coin.

The probability associated with 3 heads are:

  • 0.5^3 = 0.125 out of 0.5(fair coin).
  • 1 out of 0.5(biased).

Hence:

P(A) = 0.125 + 0.5 = 0.625

The probability of 3 heads and the fair coin is:

P(A \cap B) = 0.5(0.125) = 0.0625

Then, the conditional probability is:

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.0625}{0.625} = 0.1

0.1 = 10% probability that the chosen coin was the fair coin.

A similar problem is given at brainly.com/question/14398287

4 0
3 years ago
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