Part A:square cross-section
<span>Part B: a Rectangle cross -section</span>
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Given:
1. Combining like terms (here terms 6x and 2x both contain x, then we can combine them):

2. Distributive postulate:

The equation is

3. Zero product postulate (zero product postulate state that if a product of two factors is equal to zero, then first factor is equal to zero or second factor is equal to zero):

4. Subtraction property of equality:
a) subtract 6 from the first equation:

b) subtract 2 from the second equation:

Answer:
The center is ( 5.3, -3.3) and 7 is the radius
Step-by-step explanation:
We can write the equation of a circle as
( x-h)^2 + ( y-k)^2 = r^2
Where ( h,k) is the center and r is the radius
(x - 5.3)^2 + (y + 3.3)^2=49
(x - 5.3)^2 + (y - -3.3)^2=7^2
The center is ( 5.3, -3.3) and 7 is the radius
A because if you were doing it on a quadrant or a number line I think that would be the answer! Not 100% sorry
It would be D just add and multiply the sides by what they need to be right there you’ll get D