d- enjoy
b- national service !
Answer:
The algorithm is as follows
1. Start
2. Declare Integer N
3. Input N
4. While N > 0:
4.1 Print(N%10)
4.2 N = N/10
5. Stop
Explanation:
This line starts the algorithm
1. Start
This declares an integer variable
2. Declare Integer N
Here, the program gets user input N
3. Input N
The while iteration begins here and it is repeated as long as N is greater than 0
4. While N > 0:
This calculates and prints N modulus 10; Modulus of 10 gets the individual digit of the input number
4.1 Print(N%10)
This remove the printed digit
4.2 N = N/10
The algorithm ends here
5. Stop
<u>Bonus:</u>
The algorithm in Python is as follows:
<em>n = 102</em>
<em>while n>0:</em>
<em> print(int(n%10))</em>
<em> n= int(n/10)</em>
<em> </em>
Consistency and unity
highlight important content
Answer:
// here is code in C++.
#include <bits/stdc++.h>
using namespace std;
// main function
int main()
{
// variables
int x=5,y=2,z=9;
int min;
// find the smallest value and assign to min
// if x is smallest
if(x < y && x < z)
// assign x to min
min=x;
// if y is smallest
else if(y < z)
// assign y to min
min=y;
// if z is smallest
else
// assign z to min
min=z;
// print the smallest
cout<<"smallest value is:"<<min<<endl;
return 0;
}
Explanation:
Declare and initialize variables x=5,y=2 and z=9.Then check if x is less than y and x is less than z, assign value of x to variable "min" .Else if value of y is less than value of z then smallest value is y, assign value of y to "min".Else z will be the smallest value, assign its value to "min".
Output:
smallest value is:2
