Answer:
Following are the analogies to this question:
Explanation:
In each match, the group is a comparison because there may be a tie situation, which already implies, that its triage was unabated, 1 means the best team, and n means the worst team.
It makes it much easier to address whether another 'Quick Sort' or even the 'Merge Sort' issue by converting the very same problem throughout the number problem.
All the cases use for the Merge Sort, in which it utilizes its evenly divide or overcome strategy where the category is reciprocally divided into two parts where the number becomes measured at n==2, and the outcome extends.
Assume we get 7 squads:
2 4 5 4 3 1 6
Recursively split the above teams:
2 4 5 4 3 1 6
2 4 5 4 3 1 6
We'll equate such figures with base-case (n==2) (have a match against each other)
2 4 4 5 1 3 6 (number of matches 1(2,4) + 1(5,4) + 1(3,1) = 3)
Now the division is combined.
1, 2 ,3, 4, 4, 5
NLogN was its best time complexity of an algorithm but N is the lot of clubs.
