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Rzqust [24]
3 years ago
10

Use the counting principle to determine the number of elements in the sample space. Two digits are selected without replacement

from the digits 1, 2, 3, and 4.
Mathematics
1 answer:
kicyunya [14]3 years ago
3 0

Answer:

if the order of the digit matters, we have:

options: 1, 2, 3, 4.

We want to select two digits.

First selection: we have 4 options

Second selection: we have 3 options (because we already selected one in the first selection)

The total number of elements in the sample space, or the total number of combinations, is equal to the product of the number of options in each selection, this is:

P = 4*3 = 12

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Answer:

average = -9

lower than 5

Step-by-step explanation:

You have the following formula:

G(t)=-(t-1)^2+5

to calculate the average rate of change you first calculate the derivative:

\frac{dG}{dt}=-2(t-1)

the interval of dG/dt for −4≤t≤5 is:

t = -4

\frac{dG}{dt}=-2(-4-1)=10

t = 5

\frac{dG}{dt}=-2(5-1)=-8

the average rate of change is :

average\ =\ \frac{-8-10}{2}=-9

is lower that 5

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3 years ago
Consider the following functions:
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A car and a motor bike are priced at $19877. If the value of the car is four times the value of the motor bike, how much is the
Jlenok [28]

Answer:

4,969.25

Step-by-step explanation:

$19877 ÷ 4

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Is this a rigid transformation? Explain.
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A.

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The probability that a car has a certain factory defect is 825. The probability that a car has a certain factory defect and need
ipn [44]

Answer:

90.91% probability that a car needs an oil change given that it has a certain factory defect

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this problem, we have that:

Event A: having a factory defect.

Event B: needing an oil change.

The probability that a car has a certain factory defect is 825.

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The probability that a car has a certain factory defect and needs an oil change is 750.

So P(A \cap B) = 0.75

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