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hoa [83]
3 years ago
5

Please help me set up number 3 like number 1

Mathematics
1 answer:
Wewaii [24]3 years ago
4 0
(-2)-(3) = -5. or -2-3=-5

Have a nice day! :)
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What is the value of 9 1/2​
poizon [28]

Answer:

19\2

Step-by-step explanation:

5 0
3 years ago
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Help<br><br> (5a-3a^3)*(4a-1)
ivann1987 [24]

Answer:

-12a^{4}  + 3a^{3} + 20a^{2} -5a

Step-by-step explanation:

(5a-3a^{3} ) • (4a-1)

Let's use FOIL (first, outer, inner, last) to solve this. We'll multiply the terms by one another in that fashion.

20a^{2} - 5a - 12a^{4} + 3a^{3}

Rearrange in decreasing exponents.

-12a^{4}  + 3a^{3} + 20a^{2} -5a

3 0
3 years ago
This isn't really a question but something to kinda help you. I know with all this stuff going on with the Cov** and stuff schoo
Lisa [10]

Answer:

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6 0
3 years ago
There are two college entrance exams that are often taken by students, Exam A and Exam B. The composite score on Exam A is appro
elena55 [62]

Answer:

B.The score on Exam A is better, because the percentile for the Exam A score is higher.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

Two exams. The exam that you did score better is the one in which you had a higher zscore.

The composite score on Exam A is approximately normally distributed with mean 20.1 and standard deviation 5.1.

This means that \mu = 20.1, \sigma = 5.1.

You scored 24 on Exam A. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{24 - 20.1}{5.1}

Z = 0.76

The composite score on Exam B is approximately normally distributed with mean 1031 and standard deviation 215.

This means that \mu = 1031, \sigma = 215.

You scored 1167 on Exam B, s:

Z = \frac{X - \mu}{\sigma}

Z = \frac{1167 - 1031}{215}

Z = 0.632

You had a better Z-score on exam A, so you did better on that exam.

The correct answer is:

B.The score on Exam A is better, because the percentile for the Exam A score is higher.

3 0
3 years ago
PLS HELP I NEED HELP NOW<br> I BEG
stepan [7]
Hello there! The area of the triangle portion is 11 square units, the area of the rectangle portion is 77 square units, and the area of the entire figure is 88 square units.

To find the area of the triangle, we can follow the formula:

A = LW/2 (which means length x width divided by 2)

Given the formula:

2 • 11 = 22

22 divided by 2 gives us 11 square units.

To find the area of the rectangle portion, we can follow the area formula:

A = LW (which means area = length x width)

Given the formula:

7 • 11 = 77 square units

To find the area of the whole figure, we add the areas of both isolated shapes:

11 + 77 = 88 square units.

Therefore, our area for the entire figure is 88 square units. If you need any extra help, let me know and I will gladly assist you.
7 0
1 year ago
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