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DiKsa [7]
2 years ago
9

Sophia downloaded 600 vacation pictures. Of the pictures, 63% show the beach. About how many pictures show the beach?

Mathematics
1 answer:
Mashcka [7]2 years ago
4 0

Answer:

378 pictures

Step-by-step explanation:

600 multiplied .63

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Solve for x<br> <img src="https://tex.z-dn.net/?f=%5Cfrac%7B5x%7D%7B4%7D" id="TexFormula1" title="\frac{5x}{4}" alt="\frac{5x}{4
valkas [14]

Answer:

I've shown the process in the picture .

hope u understand

4 0
2 years ago
Enter a related multiplication sentence to solve 1/6 divided by 3
goldfiish [28.3K]

Answer:

0.05555555555

Step-by-step explanation:

usless you flip it around then it would be 2 cause 1/6 / 3 = .0555555555555 because the 1/6 butif they want u to flip it then it would be 6/3=2

6 0
2 years ago
A square pyramid. The square base has side lengths of 6 inches. The 4 triangular sides have a base of 6 inches and height of 9 i
Marrrta [24]

Answer:

The area of the pyramid’s base is 36 in².

The pyramid has 4 lateral faces.  

The surface area of each lateral face is 27 in².

Step-by-step explanation:

"<u>Lateral</u>" means side, so the lateral faces are <u>triangles</u>.

The <u>base</u> is the bottom, which is a <u>square</u>.

To calculate the <u>area of the base</u>, use the formula for area of a square.

A_{base} = s^{2}

A_{base} = (6 in)^{2}

A_{base} = 36 in^{2}

To calculate the <u>area of a lateral face</u>, find the area of a triangle.

A_{lateral} = \frac{bh}{2}

A_{lateral} = \frac{(6 in)(9 in)}{2}

A_{lateral} = \frac{54 in^{2}}{2}

A_{lateral} = 27 in^{2}

In a pyramid, the number of lateral faces is the same as the number of sides in the base. <u>The square base as 4 sides, so there are 4 lateral faces</u>.

3 0
3 years ago
What is the sum of the first five terms of a geometric series with a1 = 6 and r = 1/3? Express your answer as an improper fracti
Likurg_2 [28]

Answer:

  242/27

Step-by-step explanation:

Using the formula for the sum, you can fill in the given values and do the arithmetic.

  Sn = a1·(r^n -1)/(r -1)

  S5 = 6·((1/3)^5 -1)/(1/3 -1) = 6(-242/243)/(-2/3) = 6·(121/81)

  S5 = 242/27

_____

Or, you can write the terms and add them up. The sum is ...

  6 + 2 + 2/3 + 2/9 + 2/27 = (162 +54 +18 +6 +2)/27 = 242/27

5 0
3 years ago
What is the solution to the linear equation? 2/3x-1/2=1/3+5/6x
creativ13 [48]
2/3x - 1/2 = 1/3 + 5/6x....multiply the entire equation by the common denominator of 6...this will get rid of the fractions.

6(2/3x - 1/2) = 6(1/3 + 5/6x) =
4x - 3 = 2 + 5x...subtract 5x from both sides
4x - 5x - 3 = 2...add 3 to both sides
4x - 5x = 2 + 3...combine terms
-x = 5...multiply by -1 to make x positive
x = -5
7 0
3 years ago
Read 2 more answers
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