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3 years ago

8

List the first 5 terms of the sequence -3n -2.

2 answers:

katrin2010 [14]3 years ago

7 0

Answer:

-5,-8,-11,-14,-17

Step-by-step explanation:

-3n -2

n=1 -3(1) -2 = -3-2 = -5

n=2 -3(2) -2 = -6-2 = -8

n=3 -3(3) -2 = -9-2 = -11

n=4 -3(4) -2 = -12-2 = -14

n=5 -3(5) -2 = -15-2 = -17

mario62 [17]3 years ago

6 0

We can substitute n with each term in order.

First Term:

-3(1) - 2

-3 - 2

-5

Second Term:

-3(2) - 2

-6 - 2

-8

Third Term:

-3(3) - 2

-9 - 2

-11

Fourth Term:

-3(4) - 2

-12 - 2

-14

Fifth Term:

-3(5) - 2

-15 - 2

-17

Therefore, the sequence is -5, -8, -11, - 14, -17

Best of Luck!

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Luba_88 [7]

Step-by-step explanation:

Hey there!

The points of line AB are; (-1,-4) and (2,11).

Note:

Use double point formula and simplify it to get two eqaution.
Use condition of parallel lines, perpendicular lines to know whether the lines are parallel or perpendicular or nothing.

~ Use double point formula.

$(y - y1) = \frac{y2 - y1}{x2 - x1} (x - x1)$

~ Keep all values.

$(y + 4) = \frac{11 + 4}{2 + 1} (x + 1)$

~ Simplify it.

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Therefore this is the equation of line AB.

Now, Finding the equation of line CD.

Given;

The points of line CD are; (1,1) and (4,10).

~ Using formula.

$(y - y1) = \frac{y2 - y1}{x2 - x1}(x - x1)$

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Use condition of parallel lines.

m1= m2

Slope of equation (i)

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$m1 = \frac{ - 5}{ - 1}$

Therefore, m1 = 5

Slope of second equation.

$m2 = \frac{ - coeff \: .of \: x}{coeff \: .of \: y}$

$m2 = \frac{ - 3}{ - 1}$

Therefore, m2 = 3.

Now, m1≠m2.

So, the lies are not parallel.

Check for perpendicular.

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Therefore, they aren't perpendicular too.

So, they are neither.

<em><u>Hope </u></em><em><u>it</u></em><em><u> helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

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