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3 years ago

Calculate the density of each ball. Use the formula

Physics

2 answers:

ololo11 [35]3 years ago

8 0

Answer:

i got it wrong but it showed the right answer the answer is

first one is 0.07

second one is 1.37

you're welcome :)

Paraphin [41]3 years ago

3 0

Answer:

⇒ 0.07 g/cm3

⇒ 1.15 g/cm3

Explanation:

You might be interested in

Can two people with brown eyes have a blue eyed baby

Elena L [17]

Answer:

Yes

Explanation:

Each person has two alleles (forms of a gene) for a characteristic. We can represent them using letters.

Dominant trait are written as capitals. If a dominant allele is present in someone's genotype, the dominant trait will show.

The recessive trait only shows if a person has two recessive alleles.

Brown eyes is a dominant trait, and blue eyes is a recessive trait.

B = dominant brown eyes

b = recessive blue eyes

If someone has <u>brown</u> eyes, their genotype can be:

If someone has blue eyes, their genotype is:

The baby's genotype must be bb because it has blue eyes. <u>The baby gets one allele from each parent</u>.

See the photo for Punnett square. If the parents are both Bb, then they could each give the b allele, resulting in a blue-eyed baby.

8 0

4 years ago

Find the power load P in kilowatts of an electrical circuit that takes a current I of 17 amperes at a voltage V of 320 volts if

MA_775_DIABLO [31]

Answer: P = 5.44 KW

Explanation:

The formula for calculating power is expressed as

P = VI

where

v is the voltage

I is the current

From the information given,

v = 320

I = 17

Thus,

P = 320 x 17 = 5440 W

We would convert it to KW by dividing by 1000. It becomes

P = 5440/1000

P = 5.44 KW

6 0

1 year ago

Select the correct answer.

Eddi Din [679]

Answer:

I think it would be using a battery recet

Explanation:

7 0

3 years ago

aving established that a sound wave corresponds to pressure fluctuations in the medium, what can you conclude about the directio

vovangra [49]

Answer: Pressure fluctuations travel along the direction of propagation of the sound wave.

Explanation:

Sound wave is a type of longitudinal wave. It is defined as a wave which consist of vibrations of particles traveling through a medium( such as air, or water).

Sound wave is propagated by the alternating adiabatic compression and expansion of the medium. The COMPRESSIONS are regions of high air pressure while the RAREFACTIONS are regions of low air pressure. Therefore, Since a sound wave consists of a repeating pattern of high-pressure and low-pressure regions moving through a medium, it is sometimes referred to as a PRESSURE WAVE.

The direction of the vibrating particles is parallel to the direction of propagation and that's why it's a type of LONGITUDINAL WAVE. Therefore, the correct option that

concludes about the direction in which such pressure fluctuations travel is

(Pressure fluctuations travel along the direction of propagation of the sound wave.)

8 0

4 years ago

An ocean thermal energy conversion system is being proposed for electric power generation. Such a system is based on the standar

defon

Answer:

Explanation:

Dear Student, this question is incomplete, and to attempt this question, we have attached the complete copy of the question in the image below. Please, Kindly refer to it when going through the solution to the question.

To objective is to find the:

(i) required heat exchanger area.

(ii) flow rate to be maintained in the evaporator.

Given that:

water temperature = 300 K

At a reasonable depth, the water is cold and its temperature = 280 K

The power output W = 2 MW

Efficiency $\zeta$ = 3%

where;

$\zeta = \dfrac{W_{out}}{Q_{supplied }}$

$Q_{supplied } = \dfrac{2}{0.03} \ MW$

$Q_{supplied } = 66.66 \ MW$

However, from the evaporator, the heat transfer Q can be determined by using the formula:

Q = UA(L MTD)

where;

$LMTD = \dfrac{\Delta T_1 - \Delta T_2}{In (\dfrac{\Delta T_1}{\Delta T_2} )}$

Also;

$\Delta T_1 = T_{h_{in}}- T_{c_{out}} \\ \\ \Delta T_1 = 300 -290 \\ \\ \Delta T_1 = 10 \ K$

$\Delta T_2 = T_{h_{in}}- T_{c_{out}} \\ \\ \Delta T_2 = 292 -290 \\ \\ \Delta T_2 = 2\ K$

$LMTD = \dfrac{10 -2}{In (\dfrac{10}{2} )}$

$LMTD = \dfrac{8}{In (5)}$

LMTD = 4.97

Thus, the required heat exchanger area A is calculated by using the formula:

$Q_H = UA (LMTD)$

where;

U = overall heat coefficient given as 1200 W/m².K

$66.667 \times 10^6 = 1200 \times A \times 4.97 \\ \\ A= \dfrac{66.667 \times 10^6}{1200 \times 4.97} \\ \\ \mathbf{A = 11178.236 \ m^2}$

The mass flow rate:

$Q_{H} = mC_p(T_{in} -T_{out} ) \\ \\ 66.667 \times 10^6= m \times 4.18 (300 -292) \\ \\ m = \dfrac{ 66.667 \times 10^6}{4.18 \times 8} \\ \\ \mathbf{m = 1993630.383 \ kg/s}$

3 0

3 years ago