Answer:
B
Step-by-step explanation:
If you don't understand some steps, comment it for me please.
1. Find diagonal.
d = 2r
d = 2(9)
d = 18
2. Find length of square.
each length of square = x
![x : 18 = 1 : \sqrt{2}](https://tex.z-dn.net/?f=x%20%3A%2018%20%3D%201%20%3A%20%5Csqrt%7B2%7D)
![\frac{x}{18} = \frac{1}{\sqrt{2} }](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7B18%7D%20%3D%20%5Cfrac%7B1%7D%7B%5Csqrt%7B2%7D%20%7D)
![\sqrt{2}x = 18](https://tex.z-dn.net/?f=%5Csqrt%7B2%7Dx%20%3D%2018)
![x = \frac{18}{\sqrt{2} } = 9\sqrt{2}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B18%7D%7B%5Csqrt%7B2%7D%20%7D%20%20%3D%209%5Csqrt%7B2%7D)
3. Find area of circle and square.
Area for circle
![A = \pi r^2](https://tex.z-dn.net/?f=A%20%3D%20%5Cpi%20r%5E2)
![A = \pi (9)^2](https://tex.z-dn.net/?f=A%20%3D%20%5Cpi%20%289%29%5E2)
![A = 81\pi = 254.4690...](https://tex.z-dn.net/?f=A%20%3D%2081%5Cpi%20%3D%20254.4690...)
Area for square
![A = (length)^2](https://tex.z-dn.net/?f=A%20%3D%20%28length%29%5E2)
![A = (9\sqrt{2})^2](https://tex.z-dn.net/?f=A%20%3D%20%289%5Csqrt%7B2%7D%29%5E2)
![A = 162](https://tex.z-dn.net/?f=A%20%3D%20162)
4. Subtract area of circle to area of square.
254.4690... - 162 = 92.4690...
5. Find the shaded region.
92.4690... / 4 = 23.1172...
Rounded to the nearest hundredth = 23.12
![HEY THERE !!!](https://tex.z-dn.net/?f=%3Cb%3EHEY%20THERE%20%21%21%21)
It is a function because here in case there is a value of y for x so it is a function.
HOPE YOU LIKED.
Answer: 3246/6= 541
if u wanna know if a # is divisible by 6 or not, see if the # is divisible by 2 or 3. if it works for both, then it is divisible by 6
It looks like it wants the arc length of the circle from point P to point E. Use the fact that there are 360 deg in a circle being subdivided by the five points of the pentagon.
It's slope would be undefined.