Answer:
<u><em>All its side lengths are equal </em></u>
<u><em></em></u>
<u><em></em></u>
<u><em>(and all the agle of 60°)</em></u>
<u><em></em></u>
<u><em></em></u>
Step-by-step explanation:
What is true of an equilateral triangle? Two of its side lengths are equal. <u><em>All its side lengths are equal</em></u>. None of its side lengths are equal. None of its interior angles are equal. What is true of an equilateral triangle ? Two of its side lengths are equal . All its side lengths are equal . None of its side lengths are equal . None of its interior angles are equal .
Answer:
14,590
Step-by-step explanation:
So the best way to do these is concentration1 (%) × volume1 = concentration2 × volume2
Or C1V1 + C2V2 = C3V3, where C1 = 100% (bc ALL pecans), V1 = 6 lbs, C2 = 70%, C3 = 82%:
100%×6 + 70%×v2 = 82%×(6+v2)
100%=1.00, 70%=.7, 82%=.82
note: if none is poured out then v3 = v1+v2
6 + .7v2 = .82 (6+v2)
6 + .7v2 = 4.92 + .82v2
6 + .7v2 -.7v2 = 4.92 + .82v2 -.7v2
6 = 4.92 + .12v2
6-4.92 = 4.92-4.92 + .12v2
1.08 = .12v2
.12v2/.12 = 1.08/.12
v2 = 9 lbs
that's only v2!!!
For the final poundage, we need v3:
v3 = 6 + v2 = 6 + 9 = 15 lbs
Answer:
<em>98% of confidence intervals for the Population proportion of people who captured after appearing on the 10 most wanted list</em>
(0.3583 , 0.4579)
Step-by-step explanation:
<u>Explanation</u>:-
<em>Given sample size 'n' = 517</em>
Given data Suppose a sample of 517 suspected criminals is drawn. Of these people, 211 were captured.
'x' =211
<em>The sample proportion</em>


<em>98% of confidence intervals for the Population proportion of people who captured after appearing on the 10 most wanted list</em>


(0.4081-0.0498 , 0.4081 +0.0498)
(0.3583 , 0.4579)
<u><em>Conclusion</em></u>:-
<em>98% of confidence intervals for the Population proportion of people who captured after appearing on the 10 most wanted list</em>
(0.3583 , 0.4579)