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bija089 [108]
3 years ago
15

A tree casts a shadow 32 ft long. at the same​ time, the shadow cast by a vertical 8​-ft post is 4 ft long. find the height of t

he tree.
Mathematics
1 answer:
ale4655 [162]3 years ago
4 0
Hii mate____
.
.
.
.________
here's your answer looking for⤵
This a similar triangle problem.
If you consider the two horizontal
sides (shadows) as a ratio 32/4
Consider the corresponding vertical sides
x and 8
32/4= x/8 Cross multiply 
4x= 256
x = 64
Therefore the tree is 64 feet high.
_____
HOPE IT HELPS!! ☺☺☺✌✌
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Answer:

<u><em>All its side lengths are equal </em></u>

<u><em></em></u>

<u><em></em></u>

<u><em>(and all the agle of 60°)</em></u>

<u><em></em></u>

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Step-by-step explanation:

What is true of an equilateral triangle? Two of its side lengths are equal. <u><em>All its side lengths are equal</em></u>. None of its side lengths are equal. None of its interior angles are equal. What is true of an equilateral triangle ? Two of its side lengths are equal . All its side lengths are equal . None of its side lengths are equal . None of its interior angles are equal .​

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Alfred buys a car for £15225 which depreciates in value at a rate of 0.25% per year.
GaryK [48]

Answer:

14,590

Step-by-step explanation:

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Rina is making a nut mixture to sell at the local farmers' market. She mixes 6 pounds of pecans with a nut mixture that is 70% p
Marat540 [252]
So the best way to do these is concentration1 (%) × volume1 = concentration2 × volume2
Or C1V1 + C2V2 = C3V3, where C1 = 100% (bc ALL pecans), V1 = 6 lbs, C2 = 70%, C3 = 82%:
100%×6 + 70%×v2 = 82%×(6+v2)
100%=1.00, 70%=.7, 82%=.82
note: if none is poured out then v3 = v1+v2
6 + .7v2 = .82 (6+v2)
6 + .7v2 = 4.92 + .82v2
6 + .7v2 -.7v2 = 4.92 + .82v2 -.7v2
6 = 4.92 + .12v2
6-4.92 = 4.92-4.92 + .12v2
1.08 = .12v2
.12v2/.12 = 1.08/.12
v2 = 9 lbs
that's only v2!!!

For the final poundage, we need v3:

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7 0
2 years ago
-2x - 35 = 9 - 4x answers
dangina [55]
The answer is x=22 !!!
3 0
2 years ago
Read 2 more answers
The FBI wants to determine the effectiveness of their 10 Most Wanted list. To do so, they need to find out the fraction of peopl
koban [17]

Answer:

<em>98% of confidence intervals for the Population proportion of people who captured after appearing on the 10 most wanted list</em>

(0.3583 , 0.4579)

Step-by-step explanation:

<u>Explanation</u>:-

<em>Given sample size 'n' = 517</em>

Given data Suppose a sample of 517 suspected criminals is drawn. Of these people, 211 were captured.

'x' =211

<em>The sample proportion</em>

                                   p^{-}  = \frac{x}{n} = \frac{211}{517} =0.4081

                                  q^{-} = 1-p^{-} = 1- 0.4081 = 0.5919

<em>98% of confidence intervals for the Population proportion of people who captured after appearing on the 10 most wanted list</em>

(p^{-}  - Z_{\frac{\alpha }{2}  } \sqrt{\frac{p^{-} (1-p^{-} )}{n} } , p^{-} + Z_{\frac{\alpha }{2} } \sqrt{\frac{p^{-} (1-p^{-} }{n} } )

(0.4081  - 2.326   \sqrt{\frac{0.4081 (0.5919 )}{517} } , 0.4081+ 2.326\sqrt{\frac{0.4081(0.5919 }{517} } )

(0.4081-0.0498 , 0.4081 +0.0498)

(0.3583 , 0.4579)

<u><em>Conclusion</em></u>:-

<em>98% of confidence intervals for the Population proportion of people who captured after appearing on the 10 most wanted list</em>

(0.3583 , 0.4579)

7 0
3 years ago
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