If a random sample of 20 persons weighed 3,460, the sample mean x-bar would be 3460/20 = 173 pounds.
The z-score for 173 pounds is given by:

Referring to a standard normal distribution table, and using z = 0.66, we find:

Therefore

The answer is: 0.2546
21x -15 + 5 = 10x - 5
21x -5 = 10x
11x = 5
x = 5/11
The answer would be 40% :)
Answer:
10
Step-by-step explanation:
pi is 3.14...
pi - 1 is 2.14...
question becomes 1<2.14x and 2.14x < 10
1/2.14 < x, 0.46... < x
x < 10/2.14, x < 4.67...
combining
0.46< x < 4.67
x can be 1, 2, 3, 4