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3 years ago

-11/2 divided by 12/5.

Mathematics

2 answers:

Valentin [98]3 years ago

7 0

Answer:

Exact Form:

−55/24

Decimal Form:

−2.2916...

Mixed Number Form:

−2 7/24

Step-by-step explanation:

Reduce the expression, if possible, by cancelling the common factors.

horsena [70]3 years ago

4 0

Answer:

Hi myself Shrushtee

Step-by-step explanation:

-2.29166666667

please mark me as brainleist

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Can y’all help this is for Plato !!!!!! PLEASEEE HELP ME

irakobra [83]

The two real values that are not in the domain of the composition are x = 2 and x = -2.

<h3>What two numbers are not in the domain of f°g?</h3>

Here we have:

f(x) = 1/x

g(x) = x^2 - 4

The composition is:

f°g = f(g(x)) = 1/(x^2 - 4)

The two values that are not in the domain are the values of x such that g(x) = 0, because we can't divide by zero.

g(x) = 0 = x^2 - 4

4 = x^2

±√4 = x

±2 = x

So g(x) = 0 when x = 2 or x = -2, so these are the two real values that are not in the domain of f°g.

If you want to learn more about domains:

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2 years ago

On an averadge day, a horse might drink 50 L, a sheep might drink 4L,

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2610 L of water would be needed every day.

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3 years ago

Graph system and solution 3x+2y=14 y=1/2x+3

rodikova [14]

Answer:A

Step-by-step explanation: the answer is a

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3 years ago

Please help me with these calculus bc questions

zhannawk [14.2K]

4. Compute the derivative.

$y = 2x^2 - x - 1 \implies \dfrac{dy}{dx} = 4x - 1$

Find when the gradient is 7.

$4x - 1 = 7 \implies 4x = 8 \implies x = 2$

Evaluate $y$ at this point.

$y = 2\cdot2^2-2-1 = 5$

The point we want is then (2, 5).

5. The curve crosses the $x$ -axis when $y=0$ . We have

$y = \dfrac{x - 4}x = 1 - \dfrac4x = 0 \implies \dfrac4x = 1 \implies x = 4$

Compute the derivative.

$y = 1 - \dfrac4x \implies \dfrac{dy}{dx} = -\dfrac4{x^2}$

At the point we want, the gradient is

$\dfrac{dy}{dx}\bigg|_{x=4} = -\dfrac4{4^2} = \boxed{-\dfrac14}$

6. The curve crosses the $y$ -axis when $x=0$ . Compute the derivative.

$\dfrac{dy}{dx} = 3x^2 - 4x + 5$

When $x=0$ , the gradient is

$\dfrac{dy}{dx}\bigg|_{x=0} = 3\cdot0^2 - 4\cdot0 + 5 = \boxed{5}$

7. Set $y=5$ and solve for $x$ . The curve and line meet when

$5 = 2x^2 + 7x - 4 \implies 2x^2 + 7x - 9 = (x - 1)(2x+9) = 0 \implies x=1 \text{ or } x = -\dfrac92$

Compute the derivative (for the curve) and evaluate it at these $x$ values.

$\dfrac{dy}{dx} = 4x + 7$

$\dfrac{dy}{dx}\bigg|_{x=1} = 4\cdot1+7 = \boxed{11}$

$\dfrac{dy}{dx}\bigg|_{x=-9/2} = 4\cdot\left(-\dfrac92\right)+7=\boxed{-11}$

8. Compute the derivative.

$y = ax^2 + bx \implies \dfrac{dy}{dx} = 2ax + b$

The gradient is 8 when $x=2$ , so

$2a\cdot2 + b = 8 \implies 4a + b = 8$

and the gradient is -10 when $x=-1$ , so

$2a\cdot(-1) + b = -10 \implies -2a + b = -10$

Solve for $a$ and $b$ . Eliminating $b$ , we have

$(4a + b) - (-2a + b) = 8 - (-10) \implies 6a = 18 \implies \boxed{a=3}$

so that

$4\cdot3+b = 8 \implies 12 + b = 8 \implies \boxed{b = -4}$ .

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2 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

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