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3 years ago

89 POINTS!!! You are given an isosceles trapezoid ABCD with median XY. Complete the following.

Mathematics

1 answer:

Sauron [17]3 years ago

3 0

Answer:

(Given m∠DCB = 105, m∠DAB = 75) m∠ADC=75, m∠AXY=105, m∠DYX=105, m∠BXY=75, m∠CYX=75, m∠ABC=105

Step-by-step explanation:

Definition of consecutive interior angles

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A colony of bacteria is growing in a petri dish which has a maximum capacity of 80mg. The mass of bacteria is increasing at a ra

dolphi86 [110]

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3 years ago

I need help pleasee

AlexFokin [52]

Answer:

2x+3=-13

x=5

Step-by-step explanation:

it says 2 times a number which would be the 2x, and it says the sum of that and 3 which would be 2x+3 and it says is 13. 2x+3=13

now solving it

2x+3=13

subtract 3 from both sides

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and divide 2 from both sides

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3 years ago

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Evaluate the function graphically. <br>Find f(-3)

guapka [62]

Answer:

12x

Step-by-step explanation:

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3 years ago

Estimate the product of 2.28 × 5.59 using compatible numbers.

Ierofanga [76]

The quotient of 2.28 × 5.59 using compatible numbers is approximately 12.75

<h3>What are products?</h3>

Quotients are result derived from the multiplication of two rational or integers. Given the expression

2.28 × 5.59

Convert to fraction

2.28 × 5.59 = 228/100 ÷ 559/100
2.28 × 5.59= 127452/10000

2.28 × 5.59= 12.75

Hence the quotient of 2.28 × 5.59 using compatible numbers is approximately 12.75

Learn more on product here: brainly.com/question/673545

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3 0

2 years ago

NASA launches a rocket at t = 0 seconds. Its height, in meters above sea-level, as a function of time is given by h ( t ) = − 4.

Oliga [24]

Answer:

$\displaystyle 1)48.2 \: \: \text{sec}$

$\rm \displaystyle 2)3021.6 \: m$

Step-by-step explanation:

<h3>Question-1:</h3>

so when <u>flash down</u><u> </u>occurs the rocket will be in the ground in other words the elevation(height) from ground level will be 0 therefore,

to figure out the time of flash down we can set h(t) to 0 by doing so we obtain:

$\displaystyle - 4.9 {t}^{2} + 229t + 346 = 0$

to solve the equation can consider the quadratic formula given by

$\displaystyle x = \frac{ - b \pm \sqrt{ {b}^{2} - 4 ac} }{2a}$

so let our a,b and c be -4.9,229 and 346 Thus substitute:

$\rm\displaystyle t = \frac{ - (229) \pm \sqrt{ {229}^{2} - 4.( - 4.9)(346)} }{2.( - 4.9)}$

remove parentheses:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ {229}^{2} - 4.( - 4.9)(346)} }{2.( - 4.9)}$

simplify square:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 52441- 4( - 4.9)(346)} }{2.( - 4.9)}$

simplify multiplication:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 52441- 6781.6} }{ - 9.8}$

simplify Substraction:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 45659.4} }{ - 9.8}$

by simplifying we acquire:

$\displaystyle t = 48.2 \: \: \: \text{and} \quad - 1.5$

since time can't be negative

$\displaystyle t = 48.2$

hence,

at <u>4</u><u>8</u><u>.</u><u>2</u><u> </u>seconds splashdown occurs

<h3>Question-2:</h3>

to figure out the maximum height we have to figure out the maximum Time first in that case the following formula can be considered

$\displaystyle x _{ \text{max}} = \frac{ - b}{2a}$

let a and b be -4.9 and 229 respectively thus substitute:

$\displaystyle t _{ \text{max}} = \frac{ - 229}{2( - 4.9)}$

simplify which yields:

$\displaystyle t _{ \text{max}} = 23.4$

now plug in the maximum t to the function:

$\rm \displaystyle h(23.4)- 4.9 {(23.4)}^{2} + 229(23.4)+ 346$

simplify:

$\rm \displaystyle h(23.4) = 3021.6$

hence,

about <u>3</u><u>0</u><u>2</u><u>1</u><u>.</u><u>6</u><u> </u>meters high above sea-level the rocket gets at its peak?

5 0

2 years ago