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Crazy boy [7]
3 years ago
13

I need help! (And an explanation to get an understanding, if you don’t mind!)

Mathematics
2 answers:
enot [183]3 years ago
8 0
Answer:

I think the answer is 23 and 27

Step by step explanation:
german3 years ago
4 0

Answer:

uuuuuh I think the answer is 23 & 27???

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6) Work out 4 x 10-5 x 6 x 1012<br>Give your answer in standard form.​
julia-pushkina [17]

Answer:

4 × 5 × 6 × 1012 = 121440

= 1.2 × 10⁵

5 0
3 years ago
How could you use the Distributive Property to rewrite the expression −(8 + 12)?
Volgvan
B) -8 + (-12)
Because you just have to use the distributive property and distribute -1 to (8+12)
7 0
3 years ago
Marked price of an article is rs 1500 what is selling price with 10 %vat<br><br><br><br>​
mote1985 [20]

Answer:

if no discount is allowed

MP = SP = 1500

sp with vat = sp = vat amount

vat amount = vat% of sp

                    = 10% 0f 1500

                    = 150

sp with vat = sp = vat amount

                   = 1500 + 150

                  =   1650

8 0
3 years ago
Suppose that the population of the scores of all high school seniors who took the SAT Math (SAT-M) test this year follows a Norm
Vlad1618 [11]

Answer:

Confidence =1-\alpha=1-0.01=0.99

And then the confidence level would be given by 99%

Step-by-step explanation:

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Assuming the X follows a normal distribution

X \sim N(\mu, \sigma)

The distribution for the sample mean is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

\bar x =512 represent the sample mean

\sigma=100 represent the population standard deviation

n= 100 sample size selected.

The confidence interval is given by this formula:

\bar X \pm z_{\alpha/2} \frac{\sigma}{\sqrt{n}}   (1)

The marginof error for this case is given by Me=25.76. And we know that the formula for the margin of error is given by:

Me=z_{\alpha/2} \frac{\sigma}{\sqrt{n}}

25.76=z_{\alpha/2} \frac{100}{\sqrt{100}}

And we can find the critical value z_{\alpha/2} like this:

z_{\alpha/2}=\frac{25.76(\sqrt{100})}{100}=2.576

And we know that on the right tail of the z score =2.576 we have \alpha/2 of the total area. We can find the area on the right of the z score using this excel code:

"=1-NORM.DIST(2.576,0,1,TRUE)" or using a table of the normal standard distribution, and we got 0.004998=\alpha/2, so then \alpha=0.00498*2=0.009995 \approx 0.01, and then we can find the confidence like this:

Confidence =1-\alpha=1-0.01=0.99

And then the confidence level would be given by 99%

8 0
3 years ago
Please help will give brainliest
Olenka [21]
Give the other person brainliest just answering so they can get it
3 0
3 years ago
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