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GrogVix [38]
3 years ago
7

Of the waves shown below, which has the most energy?

Chemistry
2 answers:
Triss [41]3 years ago
5 0

Answer:

red it has to be red cuz it is the largest one out of it

myrzilka [38]3 years ago
5 0

Answer:

Apparently its Green

Explanation:

just took the test on A P E X

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Ill upvote please help
NARA [144]
Hello there.

<span>Find the average acceleration of a northbound subway train that slows from 12 m/s to 9.6 m/s in 0.9 s

</span><span>2.7 m/s2
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3 0
4 years ago
Calculate the mass of oxalic acid dihydrate needed to prepare 500.0 ml
VARVARA [1.3K]
Moles= molarity x liter
=0.2500 M x 0.500 L
= 0.1250 mol

mass C2H2O4 . 2H2O = 0.1250 mol x (126.068 g / 1 mol)
=15.76 g 
6 0
3 years ago
Read 2 more answers
How much heat is absorbed when 90.5 g of ice is heated from -11.0 °C to 145.0 °C?
Nadusha1986 [10]

Answer:

Q(total) = 283Kj

Explanation:

5 Heat Transitions …

Specific Heats => c(s) = 0.50cal/g∙⁰C,  c(l) = 1.0 cal/g∙⁰C, c(g) = 0.48 cal/g∙⁰C

Phase Transition Constants => ΔHᵪ = Heat of Fusion = 80 cal/g; ΔHᵥ = Heat of Vaporization = 540cal/g

Note => Phase change regions => no temp. change occurs when 2 phases are in contact (melting and evaporation). Only when single phase substance exists (s, l or g) does temperature change occur. See heating curve for water diagram. The increasing slopes are temperature change regions and heat flow is given by Q =mcΔT. The horizontal slopes are phase changes ( melting & evaporation) and heat flow for each of those regions is given by Q = m·ΔH. Each transition energy is calculated individually (see below) and added to obtain the total heat flow needed.

Q = mcΔT for temperature change regions of the heating curve (single phase only)

Q = m∙ΔH for phase transition regions of the heating curve (2 phases in contact)

Solid (ice) => Melting Pt  => Q(s) = mcΔT = (90.5g)(0.50cal/g∙⁰C)(11⁰C) = 478 cal

Melting (s/l) => Liquid (water) =>   Q(s/l) = m∙ΔHᵪ = (90.5g)(80cal/g) = 7240 cal

Liquid (water) => Boiling Pt => Q(l) = mcΔT = (90.5g)(1.0cal/g∙⁰C)(100⁰C) = 9050 cal

Boiling (l/g) => Gas (steam) => Q(l/g) = m∙ΔHᵥ = (90.5g)(540cal/g) = 48,870 cal

Gas (steam) => Steam @ 145⁰C => Q(g = mcΔT = (90.5g)(0.48cal/g∙⁰C)(45⁰C) = 2036 cal

Total Heat Transfer (Qᵤ) = Q(s) + Q(s/l) + Q(l) + Q(l/g) + Q(g)  

                                 = 478cal +7240cal + 9050 cal + 48,870cal + 2036cal

                                 = 67,674 cal x 4.184 j/cal = 283,148 joules = 283 Kj

4 0
4 years ago
(1.7m - 2) + (2m – 4)
Pavel [41]

Answer: 3.7 m − 6

Explanation: Simplify the expression.

brainliest or a thank you pls :)) <3

6 0
3 years ago
Given the formula 4f10, what does the 10 stand for?
egoroff_w [7]
I have not idea sorry
5 0
3 years ago
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