Answer:
about 0.7 g/mL
Explanation:
Density = mass ÷ volume
D = 5.29 g / (12.6 mL - 5.00 mL)
D = 5.29 g / 7.6 mL
D = 0.696052.... g/mL
D = about 0.7 g/mL
Answer:
1
Recall that at STP, 1 mole of any ideal gas occupies 22.4 liters. Volume O2 gas = 0.0510 moles O2 x 22.4 L/mole = 1.14 liters (3 sig.
Explanation:
hope this helps
You have to use Avogadro's number which is 6.02x10^23. The units of Avogadro's number is molecules/mole so you divide the number of molecules by Avogadro's number which will give you the number of moles.
(2.0x10^22 molecules)/(6.02x10^23 molecules/mole)=0.033 moles
1. Translate, predict the products, and balance the equation above.
Li + Cu(NO3)2 = Li(NO3)2 + Cu
2. How many particles of lithium are needed to produce 125 g of copper?
125 g Cu ( 1 mol / 63.55 g ) (1 mol Li / 1 mol Cu ) ( 6.022 x 10^23 particles / 1 mol ) = 1.18x10^24 Li particles
3. How many grams of lithium nitrate are produced from 4.83E24 particles of copper (II) nitrate?
4.83E24 particles of copper (II) nitrate ( 1 mol / 6.022x10^23 particles ) (1 mol Li(NO3)2 / 1 mol Cu(NO3)2 ) ( 130.95 g / 1 mol ) = <span>1043.77 grams Li(NO3)2</span>
