Answer:
P = 6200 / (1 + 5.2e^(0.0013t))
increases the fastest
Step-by-step explanation:
dP/dt = 0.0013 P (1 − P/6200)
Separate the variables.
dP / [P (1 − P/6200)] = 0.0013 dt
Multiply the left side by 6200 / 6200.
6200 dP / [P (6200 − P)] = 0.0013 dt
Factor P from the denominator.
6200 dP / [P² (6200/P − 1)] = 0.0013 dt
(6200/P²) dP / (6200/P − 1) = 0.0013 dt
Integrate.
ln│6200/P − 1│= 0.0013t + C
Solve for P.
6200/P − 1 = Ce^(0.0013t)
6200/P = 1 + Ce^(0.0013t)
P = 6200 / (1 + Ce^(0.0013t))
At t = 0, P = 1000.
1000 = 6200 / (1 + C)
1 + C = 6.2
C = 5.2
P = 6200 / (1 + 5.2e^(0.0013t))
You need to change the exponent from negative to positive.
The inflection points are where the population increases the fastest.
Answer:
2,250 + 95n
Step-by-step explanation:
Cost of a food booth = 100 + 2n
Cost of 10 food booth = 10(100 + 2n)
= 1,000 + 20n
Cost of a game booth = 50 + 3n
Cost of 25 game booth = 25(50 + 3n)
= 1,250 + 75n
Total amount earned by the company = Cost of 10 food booth + Cost of 25 game booth
= (1,000 + 20n) + (1,250 + 75n)
= 1,000 + 20n + 1,250 + 75n
= 1,000 + 1,250 + 20n + 75n
= 2,250 + 95n
Total amount earned by the company = 2,250 + 95n
7+ (-5) = 2.
Therefor, 4^2 would be the right answer.
They need to start the test no later than 10:10
10:10 + 1 1/2 hours = 11:40
Hope this helps
-AaronWiseIsBae
Answer:
m<2=60
m<1=120
m<3=120
Step-by-step explanation:
Since m<4=60 that transfers to m<2 also because they are equal. To find the other to angles you have to subtract 60 from 180 because m<1 and m<4 create a straight line that equals 180. That then also transfers to m<3.
Thank you have an amazing day.
