Check the picture below to the left, let's use those sides with the law of sines
![\textit{Law of sines} \\\\ \cfrac{sin(\measuredangle A)}{a}=\cfrac{sin(\measuredangle B)}{b}=\cfrac{sin(\measuredangle C)}{c} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{sin(14^o)}{97}=\cfrac{sin(84^o)}{XZ}\implies XZ = \cfrac{97\cdot sin(84^o)}{sin(14^o)}\implies XZ \approx 398.76 \\\\\\ \stackrel{\textit{now using SOH CAH TOA}}{cos(82^o) = \cfrac{XW}{XZ}}\implies XZcos(82^o)=XW \\\\\\ 398.76cos(82^o)\approx XW\implies 55.497\approx XW\implies \stackrel{\textit{rounded up}}{55=XW}](https://tex.z-dn.net/?f=%5Ctextit%7BLaw%20of%20sines%7D%20%5C%5C%5C%5C%20%5Ccfrac%7Bsin%28%5Cmeasuredangle%20A%29%7D%7Ba%7D%3D%5Ccfrac%7Bsin%28%5Cmeasuredangle%20B%29%7D%7Bb%7D%3D%5Ccfrac%7Bsin%28%5Cmeasuredangle%20C%29%7D%7Bc%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Ccfrac%7Bsin%2814%5Eo%29%7D%7B97%7D%3D%5Ccfrac%7Bsin%2884%5Eo%29%7D%7BXZ%7D%5Cimplies%20XZ%20%3D%20%5Ccfrac%7B97%5Ccdot%20sin%2884%5Eo%29%7D%7Bsin%2814%5Eo%29%7D%5Cimplies%20XZ%20%5Capprox%20398.76%20%5C%5C%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Bnow%20using%20SOH%20CAH%20TOA%7D%7D%7Bcos%2882%5Eo%29%20%3D%20%5Ccfrac%7BXW%7D%7BXZ%7D%7D%5Cimplies%20XZcos%2882%5Eo%29%3DXW%20%5C%5C%5C%5C%5C%5C%20398.76cos%2882%5Eo%29%5Capprox%20XW%5Cimplies%2055.497%5Capprox%20XW%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Brounded%20up%7D%7D%7B55%3DXW%7D)
The times plus method.... is where a mixed number.... for example, to get the improper fraction of 3 1/4, you multiply 4 and three, and add that number with 1. (try writing it on a piece of paper, times between the whole number and denominator, and a plus between the whole number and the numerator.) anyway we are going to use the reverse for this.
SO the numerator is 17, and 17 is divisible by 5..... 3 times (u get where I'm going??) and there's 2 left over so...... the answer for that one should be 3 2/5
Since 3 x 5= 15+2 is 17 ;)))
Moving ON for the one....pick like 15 or 16 to be the denominator.... and subtract the 15 or 16 from 17, and the number you get is your numerator...
Answer:
Question 2 the answer is C) y = -3/2x + 2
Question 3 the answer is D) x = 4
Step-by-step explanation:
To solve either we first need to know that parallel lines have the same slope.
So in #2 we know that the new line will also have a slope of -3/2. Therefore, we can use that along with the point given in the problem in point-slope form to get the new equation.
y - y1 = m(x - x1)
y + 1 = -3/2(x - 2)
y + 1 = -3/2x + 3
y = -3/2x + 2
And for #3, we know that we have a vertical line due to the fact that it is expressed as x = a number. Therefore, we must have the same in the answer. D is the only one that has such an answer.
Answer: a=
−by+c
/r
Step-by-step explanation: