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3 years ago

How do I mutiply 14(a+5+6b)

Mathematics

2 answers:

OLEGan [10]3 years ago

6 0

Answer:

14a + 70 + 84b

Step-by-step explanation:

Each term in the parenthesis is multiplied by 14, that is

= (14 × a) + (14 × 5) + (14 × 6b)

= 14a + 70 + 84b

padilas [110]3 years ago

4 0

Multiply 14 to each term: 14a+70+84b

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Which values of x, if any, prove that the graph below is not a function?

AleksAgata [21]

Answer:

Step-by-step explanation:

For a graph not to be a function, it means that a particular value of x has more than one corresponding value of y. Looking at the graph, at the point where x = 3 on the horizontal axis, there are so many value of y. Plus, the graph below is not a function at x = 3

The correct option is 3

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3 years ago

When a number is decreased by 4%, the result is 93. What is the original number

romanna [79]

Answer:

The original number is 96.875

Step-by-step explanation:

Let's find the original number using the Direct Rule of Three, this way:

Percentage Number

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3 years ago

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belka [17]

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4 years ago

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CAN SOMEONE HELP ME IN THIS INTEGRAL QUESTION PLS

finlep [7]

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But perhaps you'd like the surface integral treatment. Parameterize the surface by

$\vec s(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec\jmath+u^2\,\vec k$

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The precise order of the partial derivatives doesn't matter, because we're ultimately interested in the magnitude of the cross product:

$\left\|\dfrac{\partial\vec s}{\partial u}\times\dfrac{\partial\vec s}{\partial v}\right\|=u\sqrt{1+4u^2}$

Then the area of the surface is

$\displaystyle\int_0^{2\pi}\int_1^2\left\|\dfrac{\partial\vec s}{\partial u}\times\dfrac{\partial\vec s}{\partial v}\right\|\,\mathrm du\,\mathrm dv=\int_0^{2\pi}\int_1^2u\sqrt{1+4u^2}\,\mathrm du\,\mathrm dv$

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