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BigorU [14]
3 years ago
11

Is 18/30 and 3/5 equivalant

Mathematics
1 answer:
frutty [35]3 years ago
5 0

Answer:

yes

Step-by-step explanation:

They both are 0.6 in decimal form

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The polynomial (x^{2}+5x+6) is a degree of _____​
dolphi86 [110]

Answer:

\displaystyle 2

Step-by-step explanation:

You pick the HIGHEST DEGREE TERM POSSIBLE. A degree of 2 is considered a Quadratic Function.

I am joyous to assist you anytime.

8 0
3 years ago
What is the answer to this question?
Agata [3.3K]

Answer:

12

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
If XX is a binomial random variable, compute the mean, the standard deviation, and the variance for each of the following cases:
Liula [17]

Answer:

(a) The mean, variance and standard deviation of <em>X </em>are 1.60, 0.96 and 0.98 respectively.

(b) The mean, variance and standard deviation of <em>X </em>are 3.20, 0.64 and 0.80 respectively.

(c) The mean, variance and standard deviation of <em>X </em>are 1.50, 0.75 and 0.87 respectively.

(d) The mean, variance and standard deviation of <em>X </em>are 4.00, 0.80 and 0.89 respectively.

Step-by-step explanation:

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The mean, variance and standard deviation of <em>X</em> are:

\mu=np\\\sigma^{2}=np(1-p)\\\sigma=\sqrt{np(1-p)}

(a)

For <em>n</em> = 4 and <em>p</em> = 0.40 compute the mean, variance and standard deviation of <em>X </em>as follows:

\mu=np=4\times0.40=1.60\\\sigma^{2}=np(1-p)=4\times0.40\times(1-0.40)=0.96\\\sigma=\sqrt{np(1-p)}=\sqrt{0.96}=0.98

Thus, the mean, variance and standard deviation of <em>X </em>are 1.60, 0.96 and 0.98 respectively.

(b)

For <em>n</em> = 4 and <em>p</em> = 0.80 compute the mean, variance and standard deviation of <em>X </em>as follows:

\mu=np=4\times0.80=3.20\\\sigma^{2}=np(1-p)=4\times0.80\times(1-0.80)=0.64\\\sigma=\sqrt{np(1-p)}=\sqrt{0.64}=0.80

Thus, the mean, variance and standard deviation of <em>X </em>are 3.20, 0.64 and 0.80 respectively.

(c)

For <em>n</em> = 3 and <em>p</em> = 0.50 compute the mean, variance and standard deviation of <em>X </em>as follows:

\mu=np=3\times0.50=1.50\\\sigma^{2}=np(1-p)=3\times0.50\times(1-0.50)=0.75\\\sigma=\sqrt{np(1-p)}=\sqrt{0.75}=0.87

Thus, the mean, variance and standard deviation of <em>X </em>are 1.50, 0.75 and 0.87 respectively.

(d)

For <em>n</em> = 5 and <em>p</em> = 0.80 compute the mean, variance and standard deviation of <em>X </em>as follows:

\mu=np=5\times0.80=4.00\\\sigma^{2}=np(1-p)=5\times0.80\times(1-0.80)=0.80\\\sigma=\sqrt{np(1-p)}=\sqrt{0.80}=0.89

Thus, the mean, variance and standard deviation of <em>X </em>are 4.00, 0.80 and 0.89 respectively.

6 0
3 years ago
Quadrilateral ABCD is inscribed in this circle<br><br> What is the measure of angle A?
Ede4ka [16]

Answer:

The four angles of a quadrilateral sum to 360 degrees.

If A and B are right angles then (2x+1) + 148 equal 180 degrees.

Therefore angle A = 32 degrees.

 

Step-by-step explanation:

8 0
3 years ago
Calculate the distance between the points L=(-4,-1) and E =(3, 7) in the coordinate plane.
BaLLatris [955]

Answer:

10.6301458127

Step-by-step explanation:

Distance between any two points (x1, y1) and (x2,y2)  on a coordinate plane is expressed by the formula = \sqrt{(x1-x2)^2 + (y1 - y2)^2} \\

given  L=(-4,-1) and E =(3, 7

substituting value of coordinates in equation \sqrt{(x1-x2)^2 + (y1 - y2)^2} \\

we have

\sqrt{(-4 - 3)^2 + (-1 - 7)^2} \\=>\sqrt{(-7)^2 + (-8)^2} \\=>\sqrt{49 + 64} \\=>\sqrt{113} \\=>10.6301458127

Therefore  the distance between the points L=(-4,-1) and E =(3, 7) = 10.6301458127

4 0
3 years ago
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