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3 years ago

Please help and show me steps

Mathematics

2 answers:

algol [13]3 years ago

7 0

Answer:

the answer is (8x-1)/15, like the other person said. to solve this you need common denominators, by multiplying each side by the other denominator.

elixir [45]3 years ago

6 0

Hello, the answer is $\frac{8x-1}{15}$ . I will attach a photo of my work, along with an explanation of each step.

I hope this helps! If you feel this helped, feel free to give me Brainliest. Have a good day, and good luck on your assignment. :)

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Which expression is equivalent to 21 × 7?

madreJ [45]

7 x 21 is equivalent to 21 x 7
also 3 x 49

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4 years ago

The number of 7th graders attending Middlefield Science Academy this year is 130% of last year’s total. If 500 7th graders atten

allsm [11]

Answer:

B,C,D,E!

Step-by-step explanation:

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3 years ago

Read 2 more answers

The endpoints of CD are C(−4, 7) and D(0,−3).

tino4ka555 [31]

Midpoint =(\frac{x_{2}+x_{1}}{2},\frac{y_{2}+y_{1}}{2})

Answer:

Midpoints of line CD are (-2,2).

Step-by-step explanation:

The midpoints is given by

$Midpoint =(\frac{x_{2}+x_{1}}{2},\frac{y_{2}+y_{1}}{2})$

As given

The endpoints of CD are C(−4, 7) and D(0,−3).

Putting values in the above

$Midpoint =(\frac{0-4}{2},\frac{-3+7}{2})$

$Midpoint =(\frac{-4}{2},\frac{4}{2})$

Midpoints = (-2,2)

Therefore midpoints of line CD are (-2,2).

4 0

3 years ago

Read 2 more answers

What is the length of the conjugate axis?<br> <img src="https://tex.z-dn.net/?f=%5Cfrac%7B%28x-2%29%5E2%7D%7B36%7D%20-%20%5Cfrac

LuckyWell [14K]

Answer:

the length of the conjugate axis is 16

Step-by-step explanation:

We know that the general equation of a hyperbola with transverse horizontal axis has the form:

$\frac{(x-h)^2}{a^2} - \frac{(y-k)^2}{b^2} = 1$

Where the point (h, k) are the coordinates of the center of the ellipse

2a is the length of the transverse horizontal axis

2b is the length of the conjugate axis

In this case the equation of the ellipse is:

$\frac{(x-2)^2}{36} + \frac{(y+1)^2}{64} = 1$

Then

$b^2 = 64\\\\b = \sqrt{64}\\\\b = 8\\\\2b = 16$

Finally the length of the conjugate axis is 16

5 0

3 years ago

Help meh please i need hell

serg [7]

Answer:

1 3/8

Step-by-step explanation:

5 0

3 years ago