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GrogVix [38]
3 years ago
13

What is the length of the conjugate axis?

%7B%28y%2B1%29%5E2%7D%7B64%7D%20%3D1" id="TexFormula1" title="\frac{(x-2)^2}{36} - \frac{(y+1)^2}{64} =1" alt="\frac{(x-2)^2}{36} - \frac{(y+1)^2}{64} =1" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
LuckyWell [14K]3 years ago
5 0

Answer:

the length of the conjugate axis  is 16

Step-by-step explanation:

We know that the general equation of a hyperbola with transverse horizontal axis has the form:

\frac{(x-h)^2}{a^2} - \frac{(y-k)^2}{b^2} = 1

Where the point (h, k) are the coordinates of the center of the ellipse

2a is the length of the transverse horizontal axis

2b is the length of the conjugate axis

In this case the equation of the ellipse is:

\frac{(x-2)^2}{36} + \frac{(y+1)^2}{64} = 1

Then

b^2 = 64\\\\b = \sqrt{64}\\\\b = 8\\\\2b = 16

Finally the length of the conjugate axis is 16

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Find AM in the parallelogram if PN =15 and AO = 6. The diagram is not to scale.
valentinak56 [21]

Answer:

6

Step-by-step explanation:

The diagonals of a parallelogram bisect each other.

The diagonals are PN and MO. The point A divides PN into 2 equal segments as well as MO into 2 equal segments.

Since AO = 6, MA should also be equal. Hence, MA (or AM) = 6.

The correct answer is AM = 6

7 0
3 years ago
Given the sequence 3, 6... what would the 10th term be?
Yakvenalex [24]

Answer:

30

Step-by-step explanation:

That are counting by 3’s so the 10th term would be 30 because 3×10 =30

Please mark me as Brainliest:)

4 0
3 years ago
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2 years ago
Given the piecewise function above evaluate the following statements. (write "DNE" if the limit does not exist)
Sveta_85 [38]

By analyzing the graph of the function, we will see that:

  • a) DNE
  • b) 3
  • c) -1
  • d) 3
  • e) DNE
  • f) 2

<h3>How to get the limits of the given function?</h3>

Remember that when we take a limit to a given value, we approach to that value by two directions (from above and below) and see at which value the function approaches.

So, for the first limit we have:

x ⇒ -2

As you can see, if we approach from below the function tends to 4, while if we approach from above, the function tends to -1, which means that this limit does not exist. DNE.

x ⇒ 0

The function is continuous here, so the limit is equal to the value of the function in that point, which is 3

x ⇒ 2

If we approach from above and below we get the same number, which is -1, so the limit is equal to -1.

x = 2

Now we are directly evaluating the function in x = 2, and we can see that there is a jump such that f(2) = 3

x ⇒ 4

Here we have two asymptotes, one goes to infinity and the other to negative infinity, so this limit does not exist.

x ⇒ ∞

So we can't see how the function behaves for large values of x, so there is no way to answer this exactly.

If we suppose that the function does not change, we can see that we have a rational function in the right side of the image, so we can expect that as x tends to infinity, the function will tend asymptotically to 2.

Why 2?

Because the denominator becomes zero when x = 4, then when x = 5 the denominator is equal to 1.

At that point, the function is equal to 3, so the function is something like:

y = 1/(x - 4) + 2

If you want to learn more about limits, you can read:

brainly.com/question/5313449

5 0
2 years ago
My sister needs some help with her homework. Can someone lend her a hand?
Neporo4naja [7]

Answer:

600 = 10 x 60

Step-by-step explanation:

If you do 10 x 60 or 60 x 10 it'll equal 600, that's what the questons is looking for so the way it'd be written is:

6 hundreds is 10 times as much as 600.

600 = 10 x 60

Hopefully this helps! I hope you and your sister have a blessed day!

5 0
1 year ago
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