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2 years ago

Please solve the problem in the attachment. It is due on thursday.

Mathematics

2 answers:

icang [17]2 years ago

7 0

That is correct ^^^ the explainenation makes

Inessa [10]2 years ago

5 0

Answer:

A= 7

B= 8

C= 3

Step-by-step explanation:

For C: 9=C*C-->C=SQRT(9)=3

For B: Some number ending in 4 is equals to B*C, C being 3. Then, the first number that fits that criteria would be B=8, as B*C=8*3=24.

For C: Some number ending in 1 equals to A*C. Then, the first number that fits that criteria is A=7, as A*C=7*3=21.

If you now multiply ABC*ABC (783*783) you'll see that all the elements in the multiplication process as carried out in the pdf are non-zero, so our answer satisfies the conditions of the problem!

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This goes with the other question i posted 50 points brainly

Rzqust [24]

Answer:

This is a rip off but...

Step-by-step explanation:

The ocuse triangle is

5 0

2 years ago

My question is 4 * 7/5th's

miskamm [114]

Answer:

5 and 3/5ths is the answer to your question

4 0

3 years ago

To find the product of 42.12 and 10³, move the decimal point in 42.12 __ places to the right because 10³ has __ zeros.

Yakvenalex [24]

<h3>To find the product of 42.12 and 10^3, move the decimal point in 42.12 3 places to the right because 10^3 has 3 zeros</h3>

<em><u>Solution:</u></em>

Given that,

$\text{ product of } 42.12 \text{ and } 10^3$

Which means,

$42.12 \times 10^3$

Here, the exponent of 10 is positive ( which is 3)

When the exponent is positive, we have to move the decimal point to right

When you multiply a number by a power of 10, ( 10!, 10^2, and so on ) move the decimal point of the number to the right the same number of places as the number of zeros in the power of 10

Here, exponent is 3 , therefore move the decimal point right 3 places in 42.12

Therefore,

$42.12 \times 10^3 = 42120$

7 0

3 years ago

Enter an equation for the function that includes the points.Give your answer in a(b)x. In the event that a=1 , give your answer

Andrews [41]

Answer:

$f(x) = \frac{24}{25} * \frac{5}{6}^x$

Step-by-step explanation:

Given

$(x_1,y_1) = (2,\frac{2}{3})$

$(x_2,y_2) = (3,\frac{5}{9})$

Required

Write the equation of the function $f(x) = ab^x$

Express the function as:

$y = ab^x$

In: $(x_1,y_1) = (2,\frac{2}{3})$

$y = ab^x$

$\frac{2}{3} = a * b^2$ --- (1)

In $(x_2,y_2) = (3,\frac{5}{9})$

$y = ab^x$

$\frac{5}{9} = a * b^3$ --- (2)

Divide (2) by (1)

$\frac{5}{9}/\frac{2}{3} = \frac{a*b^3}{a*b^2}$

$\frac{5}{9}/\frac{2}{3} = b$

$\frac{5}{9}*\frac{3}{2} = b$

$\frac{5}{3}*\frac{1}{2} = b$

$\frac{5}{6} = b$

$b = \frac{5}{6}$

Substitute 5/6 for b in (1)

$\frac{2}{3} = a * b^2$

$\frac{2}{3} = a * \frac{5}{6}^2$

$\frac{2}{3} = a * \frac{25}{36}$

$a = \frac{2}{3} * \frac{36}{25}$

$a = \frac{2}{1} * \frac{12}{25}$

$a = \frac{24}{25}$

The function: $f(x) = ab^x$

$f(x) = \frac{24}{25} * \frac{5}{6}^x$

7 0

2 years ago

SOMEONE PLEASE HELP ME

Ostrovityanka [42]

Answer:

28, 30, 32

Step-by-step explanation:

Three consecutive even numbers are three even numbers that are next to each other. For example, 2, 4 and 6 would be 3 consecutive even numbers.

With this sort of problem, you want to try to let each number be equal to one thing and then construct the same number of equations as you have variables:

Let's let,

Integer 1 = X

Integer 2 = Y

Integer 3 = Z

X + Y + Z = 90

We also know, that

Y = X + 2

And that

Z = X + 4

Now, we can sub these equations into the first equation. We do this so that we have everything represented as the same variable.

90 = X + (X+2) + (X+4)

90 = 3X + 6

84 = 3X

28 = X

So, the numbers are 28, 30 and 32

8 0

3 years ago