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swat32
2 years ago
5

Aubrey has a new art box in the shape of a rectangular rectangular prism. The box is 12 cm space, by 20cm, 5 cm the only thing i

n the art box is a new pink eraser with the dimensions shown below. What is the volume of the art box not taken up by the eraser?
Mathematics
1 answer:
marin [14]2 years ago
5 0

Answer:

By an online search, I've found that the dimensions of the eraser are:

4cm by 2cm by 0.5cm

First, we need to remember that for a rectangular prism of length L, width W, and height H, the volume is:

V = L*W*H

We know that the measures of the box are:

12cm by 20cm by 5cm

Then we can define:

L = 12cm

W = 20cm

H = 5cm

Then the total volume of the box is:

V = 12cm*20cm*5cm = 1200 cm^3

For the eraser, we will have:

L = 4cm

W = 2cm

H = 0.5cm

Then the volume of the eraser is:

v = 4cm*2cm*0.5cm = 4 cm^3

The volume of the box that is not taken up by the eraser is equal to the difference between the volume of the box and the volume of the eraser.

Then:

Volume not taken by the eraser = V - v = 1200cm^3 - 4cm^3 = 1196cm^3

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3 years ago
George plans to cover his circular pool for the upcoming winter season. The pool has a diameter of 20 feet and the cover extends
MariettaO [177]

For the circular cover we have:

A) The area is 379.94 ft²

B) The length of the rope must be 68.2 ft

<h3>How to get the area of the cover?</h3>

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Where pi = 3.14

In this case, the diameter of the pool is 20ft, then the radius is:

R = 20ft/2 = 10ft

And it must extend 12 inches beyond, then the radius of the cover must be:

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Now, we know that 1ft = 12 in, then we can rewrite the radius as:

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Remember that the circumference of a circle of radius R is:

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Then the length of the rope will be:

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If you want to learn more about circles:

brainly.com/question/1559324

#SPJ1

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