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Feliz [49]
3 years ago
9

The orbital period, P, of a planet and the planet’s distance from the sun, a, in astronomical units is related by the formula P

= a Superscript three-halves. If Saturn’s orbital period is 29.5 years, what is its distance from the sun?
9.5 AU
19.7 AU
44.3 AU
160.2 AU
Mathematics
2 answers:
34kurt3 years ago
7 0

Answer:

ig 44.3

Step-by-step explanation:

Ivanshal [37]3 years ago
6 0

Answer:

44.3 is the one

Step-by-step explanation:

mark me and give my 5 start and heart

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X = –8, y = 7, and z = –11. x - (-z)
ZanzabumX [31]

Answer:

x - ( - z) = x + z =( - 8)+(- 11) \\  =  \boxed{ - 19}

<h2>-19 is the right answer.</h2>
3 0
3 years ago
Factor 8X squared + 10x + 2​
mojhsa [17]

Answer:

2(4x + 1)(x + 1)

Step-by-step explanation:

Given

8x² + 10x + 2 ← factor out 2 from each term

= 2(4x² + 5x + 1)

To factor the quadratic

Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term

product = 4 × 1 = 4 and sum = + 5

The factors are + 1 and + 4

Use these factors to split the x - term

4x² + x + 4x + 1 ( factor the first/second and third/fourth terms )

= x(4x + 1) + 1 (4x + 1) ← factor out (4x + 1)

= (4x + 1)(x + 1), thus

4x² + 5x + 1 = (4x + 1)(x + 1) and

8x² + 10x + 2 = 2(4x + 1)(x + 1) ← in factored form

3 0
3 years ago
12 The perimeter of a rectangle
Karo-lina-s [1.5K]

Answer:

Length = 9 cm

Width = 21 cm

Step-by-step explanation:

Length = x

Width = x + 12

Perimeter = 60 cm

2 * ( length + width )  = 60

2 * (x + x +12) = 60

         2x + 12 = 60/2 = 30

                 2x = 30 - 12 = 18

                    x = 18/2 = 9

Length = 9 cm

Width = 9 + 12 = 21 cm

4 0
3 years ago
Find the image of A (-6, 5) after two reflections, first across the line y = -5, then across the
Stolb23 [73]

Answer:

a. A'(-6,-15)

b. A''(-18,-15)

Step-by-step explanation:

The given point is A(-6,5).

We want to find the image after this point has been reflected in the line y=-5.


Recall that, the mapping for a reflection in the line y=k is


P(x,y)\rightarrow P'(x,2k-y).


This implies that,


A(-6,5)\rightarrow A'(-6,2(-5)-5).


This simplifies to,


A(-6,5)\rightarrow A'(-6,-10-5).


This will finally give us,


A(-6,5)\rightarrow A'(-6,-15).


b. We now apply the second reflection, which is a reflection in the line x=-12.


Recall again that, the reflection in the line x=k has the mapping


P(x,y)\rightarrow P'(2k-x,y).


This implies that,

A'(-6,-15)\rightarrow A''(2(-12)--6,-15).

This implies that,

A'(-6,-15)\rightarrow A''(-24+6,-15).


This will finally give us,


A'(-6,-15)\rightarrow A''(-18,-15).


See graph in attachment.






8 0
4 years ago
What is the length of line segment bc? 9 units, 11 units, 15 units, 16 units
scZoUnD [109]

Step-by-step explanation:

please mark me as brainlest

7 0
2 years ago
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