3 years ago

Find integration of (secx-1)^1/2

1 answer:

6 0

∫[(secx)−1](1/2)dx? or ∫[sec(x−1)](1/2)dx hope it works

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5 - 3(6 - 2y)

saul85 [17]

Answer:

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Step-by-step explanation:

5 - 3(6 - 2y)

Distribute;

5 - 18 + 6y

-13 + 6y OR 6y - 13

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Answer:

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Step-by-step explanation:

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