Answer:
Therefore the mass of the of the oil is 409.59 kg.
Step-by-step explanation:
Let us consider a circular disk. The inner radius of the disk be r and the outer diameter of the disk be (r+Δr).
The area of the disk
=The area of the outer circle - The area of the inner circle
= 
![=\pi [r^2+2r\triangle r+(\triangle r)^2-r^2]](https://tex.z-dn.net/?f=%3D%5Cpi%20%5Br%5E2%2B2r%5Ctriangle%20r%2B%28%5Ctriangle%20r%29%5E2-r%5E2%5D)
![=\pi [2r\triangle r+(\triangle r)^2]](https://tex.z-dn.net/?f=%3D%5Cpi%20%5B2r%5Ctriangle%20r%2B%28%5Ctriangle%20r%29%5E2%5D)
Since (Δr)² is very small, So it is ignorable.
∴
The density 
We know,
Mass= Area× density

Total mass 
Therefore

![=40\pi[ln(1+r^2)]_0^5](https://tex.z-dn.net/?f=%3D40%5Cpi%5Bln%281%2Br%5E2%29%5D_0%5E5)
![=40\pi [ln(1+5^2)-ln(1+0^2)]](https://tex.z-dn.net/?f=%3D40%5Cpi%20%5Bln%281%2B5%5E2%29-ln%281%2B0%5E2%29%5D)

= 409.59 kg (approx)
Therefore the mass of the of the oil is 409.59 kg.
First you would find the sum of 187.56 and 49.73 which is 237.29 then you subtract this number from 18.65 which is 218.64 that's your answer
Step-by-step explanation:
4p³ + 36p² + 32p
= 4p(p² + 9p + 8)
= 4p(p + 1)(p + 8).
9514 1404 393
Answer:
37°
Step-by-step explanation:
The diagonals of a rhombus are angle bisectors. Angle 1 matches the other half of angle L.
∠1 = 37°
__
Angle 2 is the complement, 53°, and angle 3 is the same as angle 2, 53°.
The diagonals of a rhombus are perpendicular bisectors of each other, so angle 4 is 90°.
Answer:
(1/4)*(e⁶ - 7)
Step-by-step explanation:
a) Given
x − y = 0 if x = 0 ⇒ y = 0
x − y = 2 if x = 0 ⇒ y = -2; if y = 0 ⇒ x = 2
x + y = 0 if x = 0 ⇒ y = 0
x + y = 3 if x = 0 ⇒ y = 3; if y = 0 ⇒ x = 3
then we show the region R in the pics 1 and 2.
b) We make the change of variables as follows
u = x + y
v= x - y
If
x - y = 0 ⇒ v = 0
x − y = 2 ⇒ v = 2
x + y = 0 ⇒ u = 0
x + y = 3 ⇒ u = 3
Where u is the horizontal axis and v is the vertical axis, the new region S is shown in the pic 3.
c) We evaluate ∫∫R (x + y)*e∧(x² - y²)dA
The procedure is shown in the pic 4, where we have to calculate the Jacobian in order to use it to get the answer.