X² + x - 12 / x² - x - 20 ÷ 3x² - 24x + 45 / 12x² - 48x - 60
x² + x - 12 / x² - x - 20 * 12x² - 48x - 60 / 3x² - 24x + 45
<u>(x² + x - 12)(12x² - 48x - 60)</u>
(x² - x - 20)(3x² - 24x + 45)
<span><u>12x^4 - 48x³ - 60x² + 12x³ - 48x² - 60x - 144x² + 576x + 720</u>
</span>3x^4 - 24x³ + 45x² - 3x³ + 24x² - 45x - 60x² + 480x - 900
<span>
<u>12x^4 - 48x³ + 12x³ - 60x² - 48x² - 144x² - 60x + 576x + 720</u></span>
3x^4 - 24x³ - 3x³ + 45x² + 24x² - 60x² - 45x + 480x - 900
<u>12x^4 - 36x³ - 252x² + 516x + 720</u>
3x^4 - 27x³ + 9x² + 435x - 900
<u>12(x^4 - 3x³ - 21x² + 43x + 60) </u>
3(x^4 - 9x³ + 3x² + 145x + 300)
<u>4(</u><span><u>x^4 - 3x³ - 21x² + 43x + 60) </u>
</span><span> (x^4 - 9x³ + 3x² + 145x + 300)</span>
Jaden Smith can't act or rap.
Solution:
Number of times a die is rolled = 20
1 - 3=A
2 - 5=B
3 - 4=C
4 - 2=D
5 - 3=E
6 - 3=F
Total number of arrangements of outcomes , when a dice is rolled 20 times given that 1 appear 3 times, 2 appears 5 times, 3 appear 4 times, 4 appear 2 times , 5 appear three times, and 6 appear 3 times
= Arrangement of 6 numbers (A,B,C,D,E,F) in 6! ways and then arranging outcomes
= 6! × [ 3! × 5! × 4!×2!×3!×3!]
= 720 × 6×120×24×72→→[Keep in Mind →n!= n (n-1)(n-2)(n-3)........1]
= 895795200 Ways
<span>B.4/7
You can check by taking 21 * 4/7 = 12 which is figure 2
</span>
Answer:
(0, -4)
Step-by-step explanation:
because the y is the vertical line. (the one that is going up and down)
and it intercepts the blue line at (0, -4)
