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ipn [44]
3 years ago
5

Enter the solutions from least to greatest. H (x)=(-4x -3)(x -3)h(x)=(−4x−3)(x−3)h, left parenthesis, x, right parenthesis, equa

ls, left parenthesis, minus, 4, x, minus, 3, right parenthesis, left parenthesis, x, minus, 3, right parenthesis \text{lesser }x =lesser x=start text, l, e, s, s, e, r, space, end text, x, equals \text{greater } x =greater x=start text, g, r, e, a, t, e, r, space, end text, x, equals
Mathematics
1 answer:
olga nikolaevna [1]3 years ago
7 0

Answer:

x=-3/4     X=3

Step-by-step explanation:

Trust me :)

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What number has a greater value? 0.00009 or 0.0001.
victus00 [196]

Answer:

The answer is .0001

Step-by-step explanation:

Since it is the closest value to 0, it is the largest number


8 0
3 years ago
Read 2 more answers
Angle XYZ is rotated 270 degrees counterclockwise about the origin to form angle X’Y’Z’. Which statement shows the measure of an
8090 [49]
It is fine that you did not include the measure of angle XYZ in your posting.

This question is testing your knowledge of the four types of transformations.
1) Translations - an item is "slid" to a new location.
2) Reflections - an item is "flipped" (usually over the x-axis or y-axis)
3) Rotations - an item is rotated, usually around the origin (the point (0,0) is the center of most rotations, especially in high school math).
4) Dilations - an item is enlarged or reduced by a certain ratio.

It the first three, the image after the transformation is congruent to the pre-image.  It has the same size and shape.  It is simply flipped, rotated, slid...

But... in the fourth, dilation, the image now has a different size.  It is still, however the same shape.

In geometry terms, after the first three transformations, the image is still "congruent" to the pre-image.  After dilation, the image is "similar" but not "congruent."

So... all that to say that when you rotate an angle around the origin, the measure of the angle doesn't change.

So the first choice is correct.  The measure of the image of the angle is the same as the measure of the angle.
<span>m∠X’Y’Z’ = m∠XYZ
</span>
7 0
3 years ago
Read 2 more answers
Please help.............
natta225 [31]

Answer:

...........

2(x + 2) + 2x = 20

6 0
3 years ago
Read 2 more answers
How do I find the variable?<br><br> N x 1/5 = 2/15<br><br> N / 1/5 = 1/3
algol [13]
First you need to get all variables on one side. You do that by multiplying the reciprocal of the fraction to everything.
N(5/1) x 1/5(5/1)=2/15(5/1)
5n=2/15 x 5/1
Then solve the multiplication problem
5n= 10/15
Then you should reduce the fraction
5n=2/3
Then divide both sides by 5
5n/5=N
2/3 divided by 5 =2/15

N=2/15




4 0
3 years ago
The physical plant at the main campus of a large state university receives daily requests to replace fluorescent light bulbs. Th
ankoles [38]

We have been given that the distribution of the number of daily requests is bell-shaped and has a mean of 38 and a standard deviation of 6. We are asked to find the approximate percentage of lightbulb replacement requests numbering between 38 and 56.

First of all, we will find z-score corresponding to 38 and 56.

z=\frac{x-\mu}{\sigma}

z=\frac{38-38}{6}=\frac{0}{6}=0

Now we will find z-score corresponding to 56.

z=\frac{56-38}{6}=\frac{18}{6}=3

We know that according to Empirical rule approximately 68% data lies with-in standard deviation of mean, approximately 95% data lies within 2 standard deviation of mean and approximately 99.7% data lies within 3 standard deviation of mean that is -3\sigma\text{ to }3\sigma.

We can see that data point 38 is at mean as it's z-score is 0 and z-score of 56 is 3. This means that 56 is 3 standard deviation above mean.

We know that mean is at center of normal distribution curve. So to find percentage of data points 3 SD above mean, we will divide 99.7% by 2.

\frac{99.7\%}{2}=49.85\%

Therefore, approximately 49.85\% of lightbulb replacement requests numbering between 38 and 56.

6 0
3 years ago
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