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abruzzese [7]
2 years ago
6

-5 3/4 - 3 1/2 =? A)2 1/4 B)-9 1/4 C)-2 1/4 D)-8 2/3

Mathematics
2 answers:
Nataliya [291]2 years ago
7 0

Answer:

-9 1/4

Step-by-step explanation:

-5 3/4 - 3 1/2

Get a common denominator

-5 3/4  - 3 1/2 *2/2

-5 3/4  - 3 2/4

-8  5/4

Rewritng

-8 4/4 - 1/4

-9 1/4

Sophie [7]2 years ago
7 0
-9 1/4 would be the answer so B)
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Find the dimensions of an American football field. The length is 200 ft more than the width, and the perimeter is 1,040 ft. Find
natka813 [3]

Answer:

The width of the football field is 160 feet.

The length of the football field is 360 feet.

Step-by-step explanation:

Let w represent width of the football field.

We have been given that the length is 200 ft more than the width, so the length of the field would be w+200.

We are also told that the perimeter is 1,040 ft. We know that football field is in form of rectangle, so perimeter of field would be 1 times the sum of length and width. We can represent this information in an equation as:

2(w+w+200)=1040

Let us solve for w.

2(2w+200)=1040

4w+400=1040

4w+400-400=1040-400

4w=640

\frac{4w}{4}=\frac{640}{4}

w=160

Therefore, the width of the football field is 160 feet.

Upon substituting w=160 in expression w+200, we will get length of field as:

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Therefore, the length of the football field is 360 feet.

7 0
3 years ago
Find the area of this regular polygon.<br> Round to the nearest tenth.<br> 8.65 mm<br> [? ]mm2
nadezda [96]

Answer:

Actually it's not polygon. it's a nonagon. With r=8.65mm″, the law of cosines gives us side a:

a=√{b²+c²−2bc×cos40°}

a=√{149.645−149.645cos40°}

Area Nonagon = (9/4)a²cos40°

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=336.70125[1−cos(40°)]cot(20°)

Applying an identity for the cos(40°) does not get us very far…

= 336.70125[1−(cos2(20°)−1)]cot(20°)

= 336.70125[2−cos2(20°)]cot(20°)

= 336.70125[2−(1−sin2(20°))]cot(20°)

= 336.70125[1+sin2(20°)]cos(20°)sin(20°)

= 336.70125[cot(20°)+sin(20°)cos(20°)]mm²

3 0
3 years ago
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