Which is the surface area of the cube?

what is the coordinate of point A after being rotated 90° clockwise, if the coordinates to begin with are (-8,-1)

lys-0071 [83]

...-1,8......................................

8 0

3 years ago

Examplelt: A wall of length 10 m was to be built across an open ground. The height of the wall is 4 m and thickness of the wall

harina [27]

Answer :

4167 bricks.

Explanation :

Since the wall with all its bricks makes up the space occupied by it, we need to find the volume of the wall, which is nothing but a cuboid.

Here,

${\qquad \dashrightarrow{ \sf{Length=10 \: m=1000 \: cm}}}$

$\qquad \dashrightarrow{ \sf{Thickness=24 \: cm}}$

$\qquad \dashrightarrow{ \sf{Height=4 m=400 \: cm}}$

Therefore,

${\qquad \dashrightarrow{ \bf{Volume \: of \: the \: wall = length \times breadth \times height}}}$

${\qquad \dashrightarrow{ \sf{Volume \: of \: the \: wall = 1000 \times 24 \times 400 \: {cm}^{3} }}}$

Now, each brick is a cuboid with Length = 24 cm, Breadth = 12 cm and height = 8 cm.

So,

${\qquad \dashrightarrow{ \bf{Volume \: of \: each \: brick = length \times breadth \times height}}}$

${\qquad \dashrightarrow{ \sf{Volume \: of \: each \: brick = 24 \times 12 \times 8 \: {cm}^{3} }}}$

So,

${\qquad \dashrightarrow{ \bf{Volume \: of \: bricks \: required = \dfrac{volume \: of \: the \: wall}{volume \: of \: each \: brick} }}}$

${\qquad \dashrightarrow{ \sf{Volume \: of \: bricks \: required = \dfrac{1000 \times 24 \times 400}{24 \times 13 \times 8} }}}$

${\qquad \dashrightarrow{ \sf{Volume \: of \: bricks \: required = \bf \: 4166.6} }}$

Therefore,

<u>The wall requires 4167 bricks. </u>

6 0

2 years ago

The ages of students in a class have been put into the frequency distribution below. age number of students 18 3 19 5 20 28 21 4

Alik [6]

14.75 years old is the average age.

4 0

4 years ago

Ally and Brett decide to go jogging along a two-mile straight path at a nearby park. Ally starts jogging before Bret

malfutka [58]

Answer:

If Brett's constant rate is greater than Ally's constant rate, he may catch up to Ally before she reaches the end of the path.

Step-by-step explanation:

If Brett's constant rate is faster than Ally's then he could catch up to her because he's going faster than Ally.

7 0

3 years ago

He number of E.coli bacteria cells in a pond of stagnant water can be represented by the function below, where A represents the

denis-greek [22]

The function that represents the number of E.coli bacteria cells per 100 mL of water as t years elapses, and is missing in the question, is:

$A(t)=136(1.123)^{4t}$

Answer:

Option A. 59%

Explanation:

The base, 1.123, represents the multiplicative constant rate of change of the function, so you just must substitute 1 for t in the power part of the function::

$A(t)=136(1.123)^{4t}$

$rate=(1.123)^{4t}=(1.123)^4=1.590$

Then, the multiplicative rate of change is 1.590, which means that every year the number of E.coli bacteria cells per 100 mL of water increases by a factor of 1.590, and that is 1.59 - 1 = 0.590 or 59% increase.

You can calculate it also using two consecutive values for t. For instance, use t =1 and t = 1

$t=1\\\\ A(1)=136(1.123)^4\\\\\\t=2\\ \\ \\A(2)=136(1.123)^8\\ \\ \\A(2)/A(1)=1.123^8/1.1123^4=1.123^4=1.590$

6 0

3 years ago