Let x be the number of snack packs, then
4 + 14x < 25
14x < 25 - 4
14x < 21
x < 21/14
x < 1.33
Answer:
m(∠AOF) = 148°
Step-by-step explanation:
From the figure attached,
CD intersects line EF at a point O.
Line CD is perpendicular to the line EF.
m(∠AOE) = 32°
m(∠COE) = 90°
Since m(∠COE) = m(∠AOE) + m(∠AOC) = 90°
32° + m(∠AOC) = 90°
m(∠AOC) = 90° - 32° = 58°
m(∠AOF) = m(∠AOC) + m(∠COF)
= 58° + 90°
= 148°
Therefore, m(∠AOF) = 148° will be the answer.
Answer:
8 students,
15 cans of juice and 11 packs of cheese cracker
Step-by-step explanation:
Mariam’s uncle donate 120 cans of juice and 90 - 2 = 88 packs of cheese cracker (eats two packs) for the school picnic.
Factor these numbers:
The greatest common factor is
so the greatest number of students who can share the food equally is 8 and each student will get 
cans of juice and 11 packs of cheese cracker.
This is a typical mixture problem where using a table is the best thing.
pints juice % juice = total % juice
juice A x .70 = .70x
juice B 60-x .95 = .95(60-x)
total 60 .75 = 60(.75)
The last row gives you a total that you need to use, so do that multiplication to get 45. You now to need to add the last columns together for rows 1 and 2 and set them equal to 45: .7x +.95(60-x) = 45. When you do that math, you'll get that x = 48. This means that you need 48 pints of juice A and 60-48 pints of juice B, which is 12 pints.
