Answer:
see the attachments for the two solutions
Step-by-step explanation:
When the given angle is opposite the shorter of the given sides, there will generally be two solutions. The exception is the case where the triangle is a right triangle (the ratio of the given sides is equal to the sine of the given angle). If the given angle is opposite the longer of the given sides, there is only one solution.
When a side and its opposite angle are given, as here, the law of sines can be used to solve the triangle(s). When the given angle is included between two given sides, the law of cosines can be used to solve the (one) triangle.
___
Here, the law of sines can be used to solve the triangle:
A = arcsin(a/c·sin(C)) = arcsin(25/24·sin(70°)) = 78.19° or 101.81°
B = 180° -70° -A = 31.81° or 8.19°
b = 24·sin(B)/sin(70°) = 13.46 or 3.64
Answer/Step-by-step explanation:
Recall: SOHCAHTOA
1. Reference angle = 70°
Adjacent side = x
Hypotenuse = 6 cm
Apply CAH. Thus,
Cos 70 = adj/hyp
Cos 70 = x/6
6 × cos 70 = x
2.05 = x
x = 2.05 cm
2. Reference angle = 45°
Adjacent side = x
Hypotenuse = 1.3 m
Applying CAH, we would have the following ratio:
Cos 45 = adj/hyp
Cos 45 = x/1.3
1.3 × cos 45 = x
0.92 = x
x = 0.92 m
3. The who diagram is not shown well. Some parts are missing, however you can still solve the problem just the same way we solved problem 1 and 2.
658-216=442
There should be 442 yards of wrapping paper left on the roll.
The answer is about 3.3333
Answer:
c. (x+3)(x+9)
Step-by-step explanation:
x^2+12x+27
The middle number is 12 and the last number is 27.
We need two numbers that...
Add together to get 12
Multiply together to get 27
Try 3 and 9:
3+9 = 12
3*9 = 27
Fill in the blanks in
(x+_)(x+_)
with 3 and 9 to get...
(x+3)(x+9)