Answer/Step-by-step explanation:
The triangle is a right triangle.
✔️m<A = 180° - (53° + 90°)
m<A = 37°
✔️Find AC using trigonometric ratio:
Reference angle = 53°
Opposite = AC
Hypotenuse = 5 m
Thus:
Sin (53) = opp/hyp
Sin (53) = AC/5
5*Sin(53) = AC
AC = 3.99 (nearest hundredth)
✔️Find BC using trigonometric ratio:
Reference angle = 53°
Hypotenuse = 5
BC = Adj
Cos (53) = adj/hyp
Cos (53) = BC/5
5*Cos(53) = BC
BC = 3.01 (nearesth hundredth)
For this case we can observe both functions in the graph.
Both functions are a straight line.
Since the function is the same then the solution for the equation f (x) = g (x) is:
x that belongs to all real numbers. NOTE: see graphic.
G+b=5716
65g+40b=341690
multiply first equation by -65
-65g-65b=371540
add that to 2nd equation
-65g-65b=-371540
<span><u>65g+40b=341690 +</u></span><u />
0g-25b=-29850
-25b=-29850
divide both sides by -25
b=1194
latter=bleacher=1194 tickets
Answer:
The expected number of siblings is 1.05 or 1 (when rounded)
Step-by-step explanation:
Given the probability distribution of siblings of students in a high school with 1500 students:
![\begin{array}{ccccccc}\text{Number of Siblings}&0&1&2&3&4&5\\ \\\text{Probabilities}&0.19&0.67&0.08&0.03&0.02&0.01\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bccccccc%7D%5Ctext%7BNumber%20of%20Siblings%7D%260%261%262%263%264%265%5C%5C%20%5C%5C%5Ctext%7BProbabilities%7D%260.19%260.67%260.08%260.03%260.02%260.01%5Cend%7Barray%7D)
To find the expected value for the number of siblings of a randomly chosen student, myltiply the number of siblings by its probability and add all these products:
![0\cdot 0.19+1\cdot 0.67+2\cdot 0.08+3\cdot 0.03+4\cdot 0.02+5\cdot 0.01\\ \\=0.67+0.16+0.09+0.08+0.05\\ \\=1.05](https://tex.z-dn.net/?f=0%5Ccdot%200.19%2B1%5Ccdot%200.67%2B2%5Ccdot%200.08%2B3%5Ccdot%200.03%2B4%5Ccdot%200.02%2B5%5Ccdot%200.01%5C%5C%20%5C%5C%3D0.67%2B0.16%2B0.09%2B0.08%2B0.05%5C%5C%20%5C%5C%3D1.05)
Thus, the expected number of siblings is 1.05 or 1 (when rounded)
Answer:
B
Step-by-step explanation:
f(x) = -(x+3)(x+1)
The zeros are -3 and -1 so we can eliminate graph a
It is negative so it points down
This eliminates graphs c and d