Answer:
355,459.33
Step-by-step explanation:
42,655.12/12 = 3554.59
3554.59*100 = 355459.33
Answer:
23 chalkboards
Step-by-step explanation:
Given:
Mean length = 5 m
Standard deviation = 0.01
Number of units ordered = 1000
Now,
The z factor =
or
The z factor =
or
Z = - 2
Now, the Probability P( length < 4.98 )
Also, From z table the p-value = 0.0228
therefore,
P( length < 4.98 ) = 0.0228
Hence, out of 1000 chalkboard ordered (0.0228 × 1000) = 23 chalkboard are likely to have lengths of under 4.98 m.
x^2 + 6xy + 8y2
4x^2 + 3xy + 2y^2 - 5x^2 + 2xy + 6y^2
= 4x^2 + 3xy + 2y^2 + -5x^2 + 3xy + 6y^2
Combine like terms:
= 4x^2 + 3xy + 2y^2 + -5x^2 + 3xy + 6y^2
= (4x^2 + -5x^2) + (3xy + 3xy) + (2y^2 + 6y^2)
= -x^2 + 6xy + 8y^2
Step-by-step explanation:
The volume of a pyramid or cone is:
V = ⅓ Ah
where A is the area of the base and h is the height.
The pyramid has a square base, so:
A = s²
A = (7 cm)²
A = 49 cm²
The height is 14 cm, so the volume is:
V = ⅓ (49 cm²) (14 cm)
V = 686/3 cm³
V ≈ 228.67 cm³
Depending on how big the center is, I would say 15.
I hope this helped!