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2 years ago

Consider the following polynomial:

Mathematics

1 answer:

Taya2010 [7]2 years ago

4 0

Answer:

degree: 5

leading coef: 5

constant: 8

leading term: 5ab^5

Step-by-step explanation:

degree is highest exponent leading coef is number in the term w highest exp, constant is the number with no variables attached and leading term is term w highest exp

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Solve F=D+Drt for t.....

Anuta_ua [19.1K]

Answer:

$t = \frac{-D+F}{Dr}$

Step-by-step explanation:

Step 1: Flip the equation.

$Drt + D = F$

Step 2: Subtract D from both sides.

$Drt + D - D = F - D$
$Drt = -D + F$

Step 3: Divide both sides by Dr.

$\frac{Drt}{Dr} = \frac{-D+F}{Dr}$
$t = \frac{-D+F}{Dr}$

6 0

2 years ago

Use the line of best fit to predict the percentage sales increase when the

agasfer [191]

Answer:

107%

Step-by-step explanation:

because if we look at the x-axis, Discount (%)

and look at 35 which is between 30 and 40

and start going up we get near 100

107%

or?

we use the two points and with that we find the slope first

$\frac{y2-y1}{x2-x1}$

plug in (20,62) and (10,32)

$\frac{32-62}{10-20}$

equals

$\frac{-30}{-10}$

simplify to 3

then we use

y - y1 = m (x - x1)

y - 62 = 3 (x - 20)

y - 62 = 3x - 60

add 60 from both sides

y - 2 = 3x

add 2 to both sides

y=3x+2

then plug in 35

y= 3(35) + 2

which is

107

6 0

2 years ago

Read 2 more answers

How to evaluate the limit

anzhelika [568]

$\displaystyle\lim_{x\to2}\frac{x^2-x+6}{x+2}$

Both the numerator and denominator are continuous at $x=2$ , which means the quotient rule for limits applies:

$\dfrac{\displaystyle\lim_{x\to2}(x^2-x+6)}{\displaystyle\lim_{x\to2}(x+2)}=\dfrac{2^2-2+6}{2+2}=\dfrac84=2$

Perhaps you meant to write that $x\to-2$ instead? In that case, you would have

$\displaystyle\lim_{x\to-2}\frac{x^2-x+6}{x+2}=\lim_{x\to-2}\frac{(x+2)(x-3)}{x+2}=\lim_{x\to-2}(x-3)=-2-3=-5$