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alexandr1967 [171]
3 years ago
13

pleaseeee helllppppppppppp!!

Mathematics
2 answers:
Eva8 [605]3 years ago
8 0

Answer:

A= equilateral triangle

B= right triangle

C= obtuse triangle

svp [43]3 years ago
6 0

Answer:

Step-by-step explanation:

For the first box, B would be incorrect, since an equilateral triangle's angle measurements would all be equal. 62+62 is 124, and a triangle needs to add up to 180. As the final angle is 56, it can't be equilateral!

For the second box, C is the incorrect answer, since it is both a right triangle and scalene. The first angle is 22, the second is 90, and the third is unknown. As it needs to add up to 180, it wouldn't be possible for the unknown angle to be 158.

For the third box, C is also incorrect, since it needs to add up to 180. 108+72+72 is not possible, since that would be much higher than the 180 total.  

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There is enough fencing to surround the dog's play yard. The yard must have a perimeter of n more than 38 feet. The length of th
Ierofanga [76]

Answer:

Step-by-step explanation:

Let y = length of side parallel to the side with no fence

    x = length of each of the other two sides

Then, y+2x = 64.  So, y = 64-2x

Area = A = xy = x(64-2x)

The graph of the area function is a parabola opening downward with a highest point and with x-intercepts (0,0) and (32,0).

By the symmetry of the parabola, the x-coordinate of the maximum point lies halfway between the x-intercepts.  

So, the area is maximized when x = 16 ft

                                            y = 64 - 2x = 32 ft

Maximum area = xy = (16)(32) = 512 ft2

To maximize the area of the garden, the side of the fence parallel to the side of the house should be 32 ft long, and the other two sides should both have length 16 ft.  

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Long N. answered • 10/06/16

TUTOR  4.5 (4)

Years of Tutoring Calculus, Algebra, Statistics, Finance and SAT Prep

SEE TUTORS LIKE THIS

For the fixed given perimeter, the maximum area which can be obtained is a square.

So for 3 sides= 64 feet

one side = 64/3

The maximum area is 64/3*64/3 square feet

4 0
2 years ago
What is the volume of the square pyramid with base edges 54 yd and slant height 45 yd?
Effectus [21]
The answer is V = 34,992 y^3

You can answer this using an online calculator - calculator soup dot com under geometry then pyramid. Select given a (side length) and s (slant height). Enter the amounts to find V (volume).

To manually compute, get the h (height) first before computing for V (volume).

h^2 = l^2 - (s/2)^2  :  l (slant height), s (base edge/side)
h = √((45^2) - (54/2)^2)
h = 36

Then find V (volume) : s (side), h (height)

V = 1/3 (s^2)(h)
V = 1/3 (54^2)(36)
V = 34,992 y^3

7 0
2 years ago
Express each product in the simplest form.
ololo11 [35]
4 is probably the answer. Hope this helps. :)
5 0
3 years ago
Read 2 more answers
Match each angle below with its measurement.
brilliants [131]
A = 90 degrees
B = 50 degrees
D = 140 degrees
E = 40 degrees
HOPE THIS HELPS!
7 0
2 years ago
Read 2 more answers
calculate the height at 3 seconds given that the rocket travels 85 feet per second and starts on a launch pad 15 feet of the gro
Airida [17]

Answer:

The height of the rocket at 3 seconds is 270 feet

Step-by-step explanation:

To calculate the height of the rocket at 3 seconds,

First, we will determine the height the rocket has traveled in 3 seconds

The height traveled by the rocket is given by

Height (h) = Velocity (v) × Time (t)

From the question,

The rocket travels 85 feet per second, that is the velocity of the rocket is 85 feet per second,

Now,

v = 85 feet / second

t = 3 seconds

Hence,

Height (h) = 85 feet /second × 3 seconds

Height = 255 feet

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But, the rocket starts on a launch pad 15 feet of the ground,

Then, the height of the rocket at 3 seconds is

255 feet + 15 feet = 270 feet.

Hence, the height of the rocket at 3 seconds is 270 feet

4 0
3 years ago
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