X^2+2x^2-5x
((x^2)+2x^2)-5x
Pull the factors out
3x^2-5x=x(3x-5)
x(3x-5)
x(3x-5)*5x^2
5x(3x-5)*x^2
Final
5x^3*(3x-5)
Answer:i dont know
Step-by-step explanation:
Answer:
Final Exam score is the response variable.
Step-by-step explanation:
The response variable is the variable of interest. It is what is being tested for given the predictor variables. The response variable is also called the dependent variable and from our question we want to predict final exam scores would improve if attendance is made mandatory or as the question says, required. The number of times attended is the independent variable while final exam score is the response variable.
Answer:
he just might be
Step-by-step explanation:
Complete Question:
A population proportion is 0.4. A sample of size 200 will be taken and the sample proportion p will be used to estimate the population proportion. Use z- table Round your answers to four decimal places. Do not round intermediate calculations. a. What is the probability that the sample proportion will be within ±0.03 of the population proportion? b. What is the probability that the sample proportion will be within ±0.08 of the population proportion?
Answer:
A) 0.61351
Step-by-step explanation:
Sample proportion = 0.4
Sample population = 200
A.) proprobaility that sample proportion 'p' is within ±0.03 of population proportion
Statistically:
P(0.4-0.03<p<0.4+0.03)
P[((0.4-0.03)-0.4)/√((0.4)(.6))/200 < z < ((0.4+0.03)-0.4)/√((0.4)(.6))/200
P[-0.03/0.0346410 < z < 0.03/0.0346410
P(−0.866025 < z < 0.866025)
P(z < - 0.8660) - P(z < 0.8660)
0.80675 - 0.19325
= 0.61351
B) proprobaility that sample proportion 'p' is within ±0.08 of population proportion
Statistically:
P(0.4-0.08<p<0.4+0.08)
P[((0.4-0.08)-0.4)/√((0.4)(.6))/200 < z < ((0.4+0.08)-0.4)/√((0.4)(.6))/200
P[-0.08/0.0346410 < z < 0.08/0.0346410
P(−2.3094 < z < 2.3094)
P(z < -2.3094 ) - P(z < 2.3094)
0.98954 - 0.010461
= 0.97908
