All categories

3 years ago

PLEASE HELP I HAVE 15 MINUTES LEFT HELP HELP PLEASE

Mathematics

2 answers:

tiny-mole [99]3 years ago

8 0

Answers are on the picture

melamori03 [73]3 years ago

3 0

Answer:

I'm sorry for answering late I just saw this but

Step-by-step explanation:

1. is 34

2. is 12

3. I really dont understand that one

But try your best and multiply and division always come first before u add and subtract

You might be interested in

Write (1/6) to the 3rd power as a product of the same factor.then find the value

Nutka1998 [239]

1/6*1/6*1/6=1/216
I HOPE THIS HELPS!

8 0

3 years ago

How many sqaure feet of carpet do you need will you need

kati45 [8]

12 ft I had the question the other day on online school :)

5 0

3 years ago

Given that 5x:9=7:3 calculate the value of x. give your answer in its simplest form.

Hitman42 [59]

$\huge\underline{\red{A}\green{n}\blue{s}\purple{w}\pink{e}\orange{r} →}$

Step-by-step explanation:

<h3>Given →</h3>

5x:9 = 7:3

→ 5x/9 = 7/3

→ x = (7 × 9)/(3 × 5)

→ x = 21/5

<h3>Hope it helps you!!</h3>

8 0

2 years ago

if an exterior angle of a triangle has a measure of 35 degrees, what is the measure of the adjacent interior angle?

Alona [7]

Answer:

145

Step-by-step explanation:

Adjacent interior angle = x

Sum of exterior angle and adjacent interior angle = 180

35 + x = 180

x = 180 - 35

x = 145

3 0

3 years ago

Read 2 more answers

Enter the correct answer in the box. solve the equation x2 − 16x 54 = 0 by completing the square. fill in the values of a and b

poizon [28]

The roots of the given polynomials exist $x=8+\sqrt{10}$ , and $x=8-\sqrt{10}$ .

<h3>What is the formula of the quadratic equation?</h3>

For a quadratic equation of the form $a x^{2}+b x+c=0$ the solutions are

$x_{1,2}=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Therefore by using the formula we have

$x^{2}-16 x+54=0$$

Let, a = 1, b = -16 and c = 54

Substitute the values in the above equation, and we get

$x_{1,2}=\frac{-(-16) \pm \sqrt{(-16)^{2}-4 \cdot 1 \cdot 54}}{2 \cdot 1}$$

simplifying the equation, we get

$$&x_{1,2}=\frac{-(-16) \pm 2 \sqrt{10}}{2 \cdot 1} \\$

$$&x_{1}=\frac{-(-16)+2 \sqrt{10}}{2 \cdot 1}, x_{2}=\frac{-(-16)-2 \sqrt{10}}{2 \cdot 1} \\$

$$&x=8+\sqrt{10}, x=8-\sqrt{10}$

Therefore, the roots of the given polynomials are $x=8+\sqrt{10}$ , and

$x=8-\sqrt{10}$ .

To learn more about quadratic equations refer to:

brainly.com/question/1214333

#SPJ4

3 0

1 year ago

Read 2 more answers