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jasenka [17]
3 years ago
10

What is the number of positive integers not larger than 210 and not divisible by 2, 3 or 7?

Mathematics
1 answer:
vladimir1956 [14]3 years ago
7 0
Number of +ve integers divisible by 2 less than or equal to 210=a=210/2=105

number of +ve integers divisible by 3 less than or equal to 210=b=210/3=70

number of +ve integers divisible by 7 less than or equal to 210=c=210/7=30

number of +ve integers divisible by 2&3 less than or equal to 210=d=210/6=35

number of +ve integer divisible by 2&7 less than or equal to 210=e=210/14=15

number of +ve integer divisible by 3&7 less than or equal to 210=e=210/21=10

number of +ve integer divisible by 2&7&3 less than or equal to 210=e=210/42=5

<span>number of positive integers not larger than 210 and divisible by 2, 3 or 7=105+70+30-(35+15+10)+5

=150

so numbers not divisible=total-150
                                         =210-150
                                         =</span>60
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Pulling out like terms:

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Trying to factor by splitting the middle term

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The middle term is,  +3x  its coefficient is  3 .

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Step-1 : Multiply the coefficient of the first term by the constant   3 • 7 = 21

Step-2 : Find two factors of  21  whose sum equals the coefficient of the middle term, which is   3 .

     -21    +    -1    =    -22

     -7    +    -3    =    -10

     -3    +    -7    =    -10

     -1    +    -21    =    -22

     1    +    21    =    22

     3    +    7    =    10

     7    +    3    =    10

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Conclusion : Trinomial can not be factored

Equation at the end of step  3  :

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We'll refer to this Equation as  Eq. #3.2.1  

The Square Root Principle says that When two things are equal, their square roots are equal.

Note that the square root of

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