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2 years ago

What is the value of this expression when x=-6 and y= -1/2? 4(x^2+3)-2y

Mathematics

2 answers:

daser333 [38]2 years ago

5 0

Answer:

Explanation:

Substituting

for

and

−

for

gives:

−

→

(

−

)

(

)

−

(

−

)

→

(

−

)

(

)

−

(

−

)

→

−

→

Hope I did not make it hard enough

Please give me Brainliest

Semmy [17]2 years ago

5 0

Answer:

157

Step-by-step explanation:

Given 4(x^2+3)-2y, substitute -6 for x and -1/2 for y:

4([-6]^2 + 3) - 2(-1/2), or

4 (36 + 3) + 1, or

4(39) + 1, or, finally, 157.

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Given that AXB is complementary to both CYD and FZE and m AXB=20 degrees what is m CYD+m FZE?

ohaa [14]

We know that AXB + CYD and AXB + FZE = 90

20 + CYD = 90 and 20 + FZE = 90

We can see that CYD and FZE are equal so we can use one equation

Let's use 20 + CYD = 90

CYD = 70 and FZE is also equal to 70 because CYD and FZE are equal.

so 70 + 70 = 140 degree

8 0

2 years ago

Read 2 more answers

Wisin estimated his cell phone bill to be $93. His actual bill was $87. What was his percent error?

Annette [7]

The percent error is: 6.89%

Step-by-step explanation:

The percent error is given by:

$Percent\ error=\frac{|Expected\ value-Exact\ value|}{Exact\ Value} *100$

Here,

Expected Value = $93

Exact Value = $87

Putting the values in the formula

$Percent\ Error=\frac{|93-87|}{87}*100\\=\frac{|6|}{87}*100\\=0.0689*100\\=6.89\%$

The percent error is: 6.89%

Keywords: Percent, Error

Learn more about percent error at:

#LearnwithBrainly

4 0

2 years ago

A used car is for sale for $24,000. Jared took a chance and offered the owner 1/4 of the selling price. How much did Jared offer

sashaice [31]

Answer:

Jared offer <u>$6,000</u>.

Step-by-step explanation:

Given:

A used car is for sale for $24,000. Jared took a chance and offered the owner 1/4 of the selling price.

Now, to find the price Jared offer.

Selling price = $24,000.

Jared offer = $\frac{1}{4}$ of selling price.

So, to get the price Jared offer:

$\frac{1}{4}\ of\ \$24000$

$=\frac{1}{4} \times 24000$

$=\frac{24000}{4}$

$=\$6000.$

Therefore, Jared offer $6,000.

6 0

3 years ago

Suppose that we have the following sequence :

Jlenok [28]

$a_n=\dfrac12a_{n-1}$
$a_n=\dfrac1{2^2}a_{n-2}$
$a_n=\dfrac1{2^3}a_{n-3}$
$a_n=\cdots=\dfrac1{2^{n-1}}a_1$
$a_n=\dfrac1{2^{n-1}}$

$b_n=b_{n-1}+\dfrac1{2^{n-1}}$
$b_n=b_{n-2}+\dfrac1{2^{n-1}}+\dfrac1{2^{n-2}}$
$b_n=b_{n-3}+\dfrac1{2^{n-1}}+\dfrac1{2^{n-2}}+\dfrac1{2^{n-3}}$
$b_n=\cdots=b_1+\dfrac1{2^{n-1}}+\dfrac1{2^{n-2}}+\cdots+\dfrac12$
$b_n=a_1+\displaystyle\sum_{k=1}^{n-1}\frac1{2^{n-k}}$
$b_n=1+\displaystyle\sum_{k=1}^{n-1}\frac1{2^{n-k}}$
$b_n=\displaystyle\sum_{k=1}^n\frac1{2^{n-k}}$
$b_n=\displaystyle\frac1{2^n}\underbrace{\sum_{k=1}^n2^k}_{S_n}$

$S_n=1+2+2^2+\cdots+2^{n-1}+2^n$
$\implies2S_n=2+2^2+2^3+\cdots+2^n+2^{n+1}$
$\implies S_n-2S_n=-S_n=1-2^{n+1}$
$\implies S_n=2^{n+1}-1$

$b_n=\dfrac{2^{n+1}-1}{2^n}=2-\dfrac1{2^n}$

$\implies b_{50}=2-\dfrac1{2^{50}}\approx1.99999999999999911182158$

$\implies b_{10^6}=2-\dfrac1{2^{10^6}}\approx2.00000000000000000000000$

8 0

3 years ago

The owner of Cardo Reef Tours found when the price for a tour was $9 US dollars per person

kotegsom [21]

Answer:

The answers for your two question problem are:

a. He should charge $7 dollars

b. Maximum value : f(5) = 130

Minimum value : f(2) = -32

Step-by-step explanation:

First problem

*When he charges $9 , the numbers of customers are an average of 1000

This means the revenue is

1000*$9 = $9000

*When he charges $7 , the numbers of customers are an average of 1500

This means the revenue is

1500*$7 = $10500

Since

$10500 > $9000

The owner should charge $7, to attract more customers and get higher revenue.

Second problem

f(x) = 2x^3 − 24x

To easily solve this problem, we can graph the equation using a calculator or any plotting tool.

Please, see attached picture

The highest point of the graph, in the interval [-3,5] corresponds to

f(5) = 130

and the lowest point :

f(2) = -32

4 0

3 years ago