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Alexxx [7]
3 years ago
8

1. Sam went for a ride on a sailboat. the ride lasted 3/4 hours'

Mathematics
1 answer:
KatRina [158]3 years ago
5 0
9/12 is number 1. and Number 2 is 1/2 =4/8 and that is 1/2 
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What is the volume of this prism? Rectangular prism composed of unit cubes. Prism is 6 units by 9 units by 7 units. units3
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The answer is:  " <span>378 units</span>³ " .
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( 6 units)  * ( 9 units) * (7 units)  = (6 * 9 * 7) units³ =  378 units³ .
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3 years ago
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Betty measured an Italian restaurant and made a scale drawing. She used the scale 2 millimeters : 1 meter. If the actual width o
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First convert all the units into millimetres.

1 metre = 1000 millimetres

10 metres = 10000 millimetres

2 : 1000 :: x : 10000

Remember this: <u><em>Product of means is equal to the product of extremes.</em></u>

<u><em></em></u>

2 × 10000 = 1000x

20000 = 1000x

∴ x = 20000 ÷ 1000

x = 20 millimetres

<u><em>PLEASE MAKE THIS ANSWER THE BRAINLIEST</em></u>

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8 0
2 years ago
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Consider the following information.
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3 years ago
A researcher wishes to estimate the average blood alcohol concentration​ (BAC) for drivers involved in fatal accidents who are f
Mnenie [13.5K]

Answer:

A 90% confidence interval for the mean BAC in fatal crashes in which the driver had a positive BAC is [0.143, 0.177] .

Step-by-step explanation:

We are given that a researcher randomly selects records from 60 such drivers in 2009 and determines the sample mean BAC to be 0.16 g/dL with a standard deviation of 0.080 ​g/dL.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                               P.Q.  =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~   t_n_-_1

where, \bar X = sample mean BAC = 0.16 g/dL

            s = sample standard deviation = 0.080 ​g/dL

            n = sample of drivers = 60

            \mu = population mean BAC in fatal crashes

<em>Here for constructing a 90% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation. </em>

So, a 90% confidence interval for the population mean, \mu is;

P(-1.672 < t_5_9 < 1.672) = 0.90  {As the critical value of t at 59 degrees of

                                              freedom are -1.672 & 1.672 with P = 5%}    P(-1.672 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 1.672) = 0.90

P( -1.672 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 1.672 \times {\frac{s}{\sqrt{n} } } ) = 0.90

P( \bar X-1.672 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+1.672 \times {\frac{s}{\sqrt{n} } } ) = 0.90

<u>90% confidence interval for</u> \mu = [ \bar X-1.672 \times {\frac{s}{\sqrt{n} } } , \bar X+1.672 \times {\frac{s}{\sqrt{n} } } ]

                                       = [ 0.16-1.672 \times {\frac{0.08}{\sqrt{60} } } , 0.16+1.672 \times {\frac{0.08}{\sqrt{60} } } ]

                                       = [0.143, 0.177]

Therefore, a 90% confidence interval for the mean BAC in fatal crashes in which the driver had a positive BAC is [0.143, 0.177] .

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