hey i need help finishing this question on my exit ticket asap please i don’t want no links just the answer

It is 4:12 p.m. Emma's mom will be home from work in 70 minutes, and Emma has gymnastics lessons at 6:00 p.m.

egoroff_w [7]

Answer:

emma is dum as freak

Step-by-step explanation:

.................................................

8 0

3 years ago

Which input value produces the same output value for the

USPshnik [31]

Answer:

x = 4

Step-by-step explanation:

The 2 graphs have the same output, y = 3 at the point of intersection

This occurs when the input is x = 4

8 0

3 years ago

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Jared bought 7 cans of paint. A can of red paint costs $3.75. A can of black paint costs $2.75. Jared spent $22.25 in all. How m

geniusboy [140]

Answer:

b = 4

r = 3

Step-by-step explanation:

r + b = 7

solve for 'r' to get r = 7-b

now substitute '7-b' for r in the second equation:

3.75(7-b) + 2.75b = 22.25

26.25 - 3.75b + 2.75b = 22.25

-b = -4

b = 4

r = 3

4 0

3 years ago

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A bacteria culture starts with 660 bacteria and grows at a rate proportional to its size. After 6 hours there will be 3960 bacte

scoray [572]

Answer:

a) $P(t) = 660 e^{\frac{ln(6)}{6} t}$

b) $P(t=3) = 660 e^{\frac{ln(6)}{6}*3} = 1616.663 \approx 1617$

Step-by-step explanation:

For this case we have the following info:

$P(0) = 660$ represent the initial amount of bacteria

$P(6) = 3960$ represent the population of bacteria after 6 hours

Part a

For this case we use the proportional model given by:

$\frac{dP}{dt}= kP$

Where P represent the population at time t and k is a constant of proportionality.

We can rewrite the model like this:

$\frac{dP}{P} = k dt$

And if we integrate both sides we got:

$ln |P|= kt + C$

Now if we apply exponential we got:

$P = e^{kt +c}= e^{kt} e^C$

$P(t)= P_o e^{kt}$

For this case using the initial condition:

$660 = P_o e^{0k}, P_o = 660$

We have the following model:

$P(t) = 660 e^{kt}$

Using the second condition $P(6) = 3960$ we have this:

$3960 = 660e^{6k}$

We can divide both sides by 660 and we got:

$6= e^{6k}$

Now we can apply natural log on both sides and we got:

$ln (6)= 6k$

$k = \frac{ln(6)}{6}=0.2986265782$

So then the model would be given by:

$P(t) = 660 e^{\frac{ln(6)}{6} t}$

Part b

For this case we just need to replace t=3 into the model and we got:

$P(t=3) = 660 e^{\frac{ln(6)}{6}*3} = 1616.663 \approx 1617$

4 0

3 years ago

What is the correct answer to 20÷2(5+5)?

poizon [28]

Answer:

To answer the question above, we need to know about the rules of mixed count operation. In mixed count operation, we can find plus [+], minus [-], divided [:], multiplication [x] and parenthesis [(...)]. For example, if the operation is: 7 x 5 + 3 - (4 x 3) : 6 = ...

first, we must finish the operation inside the parenthesis symbol, which is (4 x 3), the result is 12

second, we must finish the operation with the multiplication or divided symbol but, if both exist we must finish the far left-side first. for this example is to finish "7 x 5 = 35" first, then finish the next operation with divided symbol "(4 x 3) : 6 = 12 : 6 = 2"

for the last, we finish the operation with plus or minus symbol, but if both exist then we must finish the far left-side first. For this example is to finish "35 + 3 = 38", then finish the next operation which is "38 - 2 = 36".

there are the rules of mixed count operations, to make it clear we finish the example operation step by step

7 x 5 + 3 - (4 x 3) : 6 = ...

7 x 5 + 3 - 12 : 6 = ...

35 + 3 - 12 : 6 = ....

35 + 3 - 2 = ...

38 - 2 = 36.

now the answer to the mixed count operation above 20 : 2 (5 + 5) = ...

20 : 2 x (5 + 5) = ...

20 : 2 x 10 = ...

10 x 10 = 100

the answer of the operation is 100

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Answer Details

Subject: Mathematics

Chapter: Mixed Count Operation

Grade: High School

Keyword: What is the correct answer of 2 2?, How do you explain a math problem?, Do you use Bodmas if there are no Brackets?

7 0

4 years ago

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